We have that
the expression 2f + 4f + 2 – 3-------> we can group it (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]
if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17
<span>let's check it
</span>[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok
5/15 and -1/3 because 5 dived by 5 =1 and 15 dived by 5=3 so it’d be positive and negative 1/3
Answer: x=3
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
- Multiply both sides of the equation by 3:
- Now you must make the equation equal to zero as following:
- Factor it, as you can see below. Therefore, you obtain the following result:
Answer:
7
Step-by-step explanation:
When you match the form
... ax² + bx + c = 0
to the equation
... 3x² + 5x + 7 = 0
it is reasonable to conclude that ...
... a = 3, b = 5, c = 7.
_____
The question presumes you are familiar with the form
... ax² +bx +c = 0
which is often used as the representation of a general quadratic equation. This lets us use a, b, and c instead of specific numbers, to talk about ways of factoring, graphing, or solving equations like this.
