Answer:
Perimeter of polygon B = 80 units
Step-by-step explanation:
Since both polygons are similar, their corresponding sides and perimeters are proportional. Knowing this we can setup a proportion to find the perimeter of polygon B.

Let
be the perimeter of polygon B. We know from our problem that the side of polygon A is 24, the side of polygon B is 15, and the perimeter of polygon A is 128.
Let's replace those value sin our proportion and solve for
:





We can conclude that the perimeter of polygon B is 80 units.
You can divide 110 by 1 to see how many 1's go in 110:
110/1 = 110
This means that there are 110 1's in 110.
Hope this helps! :)
Let x be the <span>heights of a maple tree and y be the height of the cherry tree.
We know:
</span>

<span>The new ratio is obtained like this:
</span>

.
From the above equation we get

.
then

Solving the above equation for y we get:

So
So the first tree is (400-160=240) more taller than cherry tree.
The perimeter of the equilateral triangle will be 76.2 in
<u>Explanation:</u>
Altitude of an equilateral triangle, H = 22 in
Perimeter, p = ?
Let a be the side of the triangle
We know:

Perimeter = 3a
P = 3 X 25.4 in
P = 76.2 in