Write the equations in graphing form, then state the vertex of the parabola or the center and radius of the circle.
1 answer:
All we need is to put this form in the vertex form f(x) = (ax+b)^2 + c
So we have <span>f (x)= 3x^2+12x+11 ....
Let's complete the square (if you aware of it)
</span><span>
f(x)= 3x^2+12x+11 = 3(x^2+4x)+11 = 3(x^2+4x+4-4)+11
=</span><span> 3([x^2+4x+4]-4)+11 = 3[(x+2)^2-4]+11 =3</span><span>(x+2)^2 - 12 +11 = 3</span><span><span>(x+2)^2 -1
so our form would be:
Here is a parabola with vertex of (-2,-1) and with positive </span> slope (concave up)
</span>
So we have <span>f (x)= 3x^2+12x+11 ....
Let's complete the square (if you aware of it)
</span><span>
f(x)= 3x^2+12x+11 = 3(x^2+4x)+11 = 3(x^2+4x+4-4)+11
=</span><span> 3([x^2+4x+4]-4)+11 = 3[(x+2)^2-4]+11 =3</span><span>(x+2)^2 - 12 +11 = 3</span><span><span>(x+2)^2 -1
so our form would be:
Here is a parabola with vertex of (-2,-1) and with positive </span> slope (concave up)
</span>
I hope that helps!
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Answer:
A.
C.
Step-by-step explanation:
Given:
The given line is
Express this in slope-intercept form , where m is the slope and b is the y-intercept.
Therefore, the slope of the line is .
Now, for perpendicular lines, the product of their slopes is equal to -1.
Let us find the slopes of each lines.
Option A:
On comparing with the slope-intercept form, we get slope as .
Now, . So, option A is perpendicular to the given line.
Option B:
For lines of the form , where, a is a constant, the slope is undefined. So, option B is incorrect.
Option C:
On comparing with the slope-point form, we get slope as .
Now, . So, option C is perpendicular to the given line.
Option D:
On comparing with the slope-intercept form, we get slope as .
Now, . So, option D is not perpendicular to the given line.