What was the first mall

2 answers:

8 0

The first shopping mall was the Country Club Plaza, founded by the J.C. Nichols Company and opened near Kansas City, Mo., in 1922

KatRina [158]3 years ago

4 0

Country Club Plaza...

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2 - ( - 8 ) + ( - 3 ) =

solmaris [256]

Hey!

First, let's write the problem.
$2-\left(-8\right)+\left(-3\right)$
We know that, $-\left(-8\right)=+8$ , so let's apply that
$=2+8+\left(-3\right)$
We have to add, $2+8=10$
$=10+\left(-3\right)$
We know that $+\left(-3\right)=-3$ , so let's apply that.
$=10-3$
Subtract. $10-3=7$
$=7$

Our final answer would be 7!

Thanks!
-TetraFish

3 0

3 years ago

105.6 L/h = ___ L/min?

Drupady [299]

$(\frac{105.6\ L}{hour})(\frac{1\ hour}{60\ minutes})$

The hours cancel out and you divide 105.6 by 60 to get

1.76 L/min

5 0

3 years ago

What is the result when 2/5x + 1 1/4 is subtracted 2/38x - 4 1/9? (NEED ASAP)

Katyanochek1 [597]

Answer:

33 x/ 95 − 103/ 36

Step-by-step explanation: i had too many steps and i cant type them all out.

This answer is only correct if you are talking about subtracting.

7 0

3 years ago

Solve this for Brainliest! See the attachment [Level - GCSE]

madreJ [45]

Answer:

$x = 3 + 4\sqrt{3}$

Step-by-step explanation:

OPQ is a right angle triangle.

Using Pythagoras

$x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0$

Using quadratic formula

$x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}$