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devlian [24]
3 years ago
9

A contractor construct to build a house in 30 days. He employed 10 men to build the house. After 20 days. They completed only 1

/3 of the total work. How many more men will be required to finish the remaining work within due time?
Mathematics
1 answer:
ozzi3 years ago
8 0

Answer:

30

Step-by-step explanation:

First, we can say that because the men do 1/3 of the work in 20 days,

for 10 men:

20 days = 1/3 total work

Because we need the house built in 30 days, and 20 days have already passed, we only have 30-20=10 days left. Furthermore, 20/2=10, so in our equation of 20 days = 1/3 total work, we can divide both sides by 2 to get

10 days = 1/6 total work

The amount of work we need to get done in 10 days is (all of it) - (1/3 of total work) = 1 - 1/3 = 2/3 = 4/6

Since 10 men can do 1/6 of the work in 10 days, 10*4 =40 men can do 1/6 * 4 = 4/6 of the work in 10 days. This is the amount of work that needs to get done. Therefore, the contractor needs 40 (total workers) - 10 (current workers) = 30 new workers to finish the remaining work in due time

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Gasoline car = Exponential function (increasing cost)

Step-by-step explanation:

The given data the Electric car, we have;

Time (years)   {}     Cost (thousands of dollars)

0                           {}      35

5                           {}      27

10                           {}     21

15                           {}     16

20                           {}    12.5

The difference between successive term is such that each term decreases by approximately the same percentage given as follows

1st and 2nd term (35 - 27)/35 × 100 ≈ 22.8571% decrease

2nd and 3rd term (27 - 21)/27 × 100 ≈ 22.222% decrease

3rd and 4th term (21 - 16)/21 × 100 ≈ 23.81% decrease

4th and 5th term (16 - 12.5)/16 × 100 ≈ 21.875% decrease

Therefore. the electric car is best approximated by exponential function

The given data the Gasoline car, we have;

Time (years)   {}     Cost (thousands of dollars)

0                           {}      35

5                           {}      40.2

10                           {}    46.3

15                           {}    53.2

20                           {}    61.2

The difference between successive term is such that each term increases by approximately the same percentage given as follows

1st and 2nd term (40.2 - 35)/35 × 100 ≈ 14.857% decrease

2nd and 3rd term (46.3 - 40.2)/40.2 × 100 ≈ 15.174% decrease

3rd and 4th term (53.2 - 46.3)/46.3× 100 ≈ 14.9% decrease

4th and 5th term (61.2 - 53.2)/53.2× 100 ≈ 15.03% decrease

Therefore. the Gasoline car is best approximated by exponential function

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