Consider a rectangle whose length, L, is 4 more than twice its width, w. a. Write an expression for L in terms of w. b. Show tha
t the perimeter, P, is equal to = 6 + 8. c. Given the perimeter is 20, find the length and width of the rectangle using your answer to part b.
1 answer:
Answer:
Step-by-step explanation:
a)L=2w+4
b)P=2L+2w
sub L=2w+4,
P=2(2w+4)+2w
P=4w+8+2w
P=6w+8
c) 20=6w+8
12=6w
2=w
L=2(2)+4
=8
Hence,
L=8 and w=2
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