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3 years ago

Using examples, describe the following.

Mathematics

1 answer:

Hunter-Best [27]3 years ago

4 0

Answer:

1. An intuitive understanding of number, their magnitude, relationships, and how they are affected by operations.

2. The ability to work outside the traditionally taught algorithms.

3. The ability to perform mental mathematics

4. The ability to look at the world and make comparisons.

5. (In non-human animals) The ability to perceive changes in the number of things in a collection.

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8.4^3×4.8^2=<br>can you pleas help

ira [324]

Answer:

13655.90016

Step-by-step explanation:

$8.4^3 \times 4.8^2 \\= 592.704 \times 23.04\\=13655.90016$

3 0

3 years ago

Blood is a buffer solution. When carbon dioxide is absorbed into the bloodstream, it produces carbonic acid and lowers the pH. T

Irina18 [472]

Answer:

x ≅ 20.10 torr

Step-by-step explanation:

Given that the equation which models blood pH in the question is;

pH(x)=6.1+log(800/x)

where;

pH = 7.7

x = partial pressure of carbon dioxide in arterial blood, measured in torr.

we are asked to find (x)

In order to do that, we use the given equation:

pH(x)=6.1+log(800/x)

since pH = 7.7

7.7 = 6.1 + log (800/x)

7.7 - 6.1 = log (800/x)

1.6 = log (800/x)

$10^{1.6}= \frac{800}{x}$

$x= \frac{800}{10^{1.6}}$

x = 20.09509145

x ≅ 20.10 torr

4 0

3 years ago

Rearrange the formula, a=1/2bh , to solve for b in terms of A and h.

Kryger [21]

Multiply both sides by 2 to cancel out the 1/2 and you get 2a=bh then divide both sides by h to isolate b and you get (2a)/h=b

7 0

3 years ago

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

3 years ago

In this fulcrum, for the weights to be balance, what do the distances d1 and d2 have to be if the overall length is 12 feet?

mel-nik [20]

For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.

Let d1= x. since total distance is 12, we can write d2 = 12 - x

for the fulcrum to balance:

60x = 50(12 - x)

60x = 600 - 50x

110x = 600

x = 5.45

Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55

d1 = 5.45
d2 = 6.55

5 0

3 years ago

Read 2 more answers