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saw5 [17]
3 years ago
10

drew and Evelyn measured the wingspans of their butterflies. How do the wingspans compare? theirs a monarch butterfly and a swal

lowtail butterfly.
Mathematics
2 answers:
tangare [24]3 years ago
5 0

Answer:

the wingspan of drew's butterfly is 8 millimeters smaller than the wingspan of evelyn's butterfly

Step-by-step explanation:

drew's monarch butterfly is 94 mm wide  because 10 x 9.4 = 94

evelyn's swallowtail buttefly is 102 mm wide so,

102 - 94 = 8

therefore, the answer is 8 .

Rina8888 [55]3 years ago
3 0

I believe they compare because both butterflies can have a wingspan of 3.5 in. Hope this helps

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So for this, we will be applying the Triangle Inequality Theorem, which states that the sum of 2 sides must be greater than the third side for it to be a triangle. If any inequality turns out to be false, then the set cannot be a triangle.

A+B>C\\A+C>B\\B+C>A

<h2>First Option: {6, 10, 12}</h2>

Let A = 6, B = 10, and C = 12:

6+10>12\\16>12\ \textsf{true}\\\\6+12>10\\18>10\ \textsf{true}\\\\12+10>6\\22>6\ \textsf{true}

<h2>Second Option: {5, 7, 10}</h2>

Let A = 5, B = 7, and C = 10

5+7>10\\12>10\ \textsf{true}\\\\5+10>7\\15>7\ \textsf{true}\\\\10+7>5\\17>5\ \textsf{true}

<h2>Third Option: {4, 4, 9}</h2>

Let A = 4, B = 4, and C = 9

4+4>9\\8>9\ \textsf{false}\\\\4+9>4\\13>4\ \textsf{true}\\\\4+9>4\\13>4\ \textsf{true}

<h2>Fourth Option: {2, 3, 3}</h2>

Let A = 2, B = 3, and C = 3

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<h2>Conclusion:</h2>

Since the third option had an inequality that was false, <u>the third option cannot be a triangle.</u>

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