<em>1452 feet</em>
- Step-by-step explanation:
<em>1 hour = 60min×60sec = 3600 sec</em>
<em>1 miles = 5280 feet</em>
<em>22 miles = 22×5280ft = 116160 ft</em>
<em />
<em>3600sec ................. 116160 ft</em>
<em>45sec ................................ x ft</em>
<em>x = 45×116160/3600</em>
<em>= 5227200/3600</em>
<em>= 1452 feet</em>
Answer:
The bottle of perfume A contains more glass
Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four triangular faces
step 1
Find the surface area of Perfume A
![SA=3^{2} +4[\frac{1}{2}(3)(2.5)]=24\ in^{2}](https://tex.z-dn.net/?f=SA%3D3%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%283%29%282.5%29%5D%3D24%5C%20in%5E%7B2%7D)
step 2
Find the surface area of Perfume B
![SA=2.5^{2} +4[\frac{1}{2}(2.5)(3)]=21.25\ in^{2}](https://tex.z-dn.net/?f=SA%3D2.5%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%282.5%29%283%29%5D%3D21.25%5C%20in%5E%7B2%7D)
step 3
Compare the surface areas
![24\ in^{2}>21.25\ in^{2}](https://tex.z-dn.net/?f=24%5C%20in%5E%7B2%7D%3E21.25%5C%20in%5E%7B2%7D)
therefore
The bottle of perfume A contains more glass
Answer:
1. 1 tablespoon Dijon mustard
2. Combine six Tablespoons of cocoa powder and two Tablespoon of vegetable oil, butter or shortening
3. 2 cups of all-purpose flour, 3 teaspoons baking powder, and ½ teaspoon salt
3. One teaspoon of dried basil leaves
4. Combine 1 3/4 cups all-purpose flour with 1/4 cup cornstarch
Step-by-step explanation:
CAn I have brainliest? TYSMMMMMMMMMM
Answer:
17.907082 unit
Step-by-step explanation:
According to the Question,
Given, A circle with centre F, ∠EFG=54 and EF=19 .
length of arc EG = Radius(EF) × ∠EFG(in Radian)
- We Know, 1 degree = 0.0174533 Radian
- 54 degree = 0.942478 Radian
length of arc EG = 19 x 0.942478 ⇔ 17.907082 unit
(For Diagram please find in attachment)
Answer:
Step-by-step explanation:
Statements Reasons
AB // DC Given
AD // BC Given
AC ≅ AC Reflexive property
∠BAC ≅ ∠DCA Alternate interior angles
∠ACB ≅ ∠DAC Alternate interior angles
ΔCAB ≅ ΔDAC A S A
AD ≅ BC CPCT