HELP ASAP!

Graph the equation <br><br>2x + 3y = 9

jeka57 [31]

$2x + 3y = 9\\3y = -2x + 9\\y = -\frac{2}{3}x + 3$

Look at the graph picture I attached

$y = mx + c$

c is the intercept, which is why the graph crosses the y-axis at +3

to find where it crosses the x-axis, we make y = 0

$y = 0\\\to -\frac{2}{3}x + 3 = 0\\-\frac{2}{3} = -3\\\frac{2}{3}x = 3\\2x = 9\\x = \frac{9}{2}\ \ (=4.5)$

8 0

2 years ago

Pls help! I need help with a and c I did b already!

laila [671]

Answer:

A= y= -2x+7.

B= y= - $\frac{3}{2}$ x+ 6

Step-by-step explanation:

The linear equation is y=mx+b

A= y= -2x+7.

-2 represents he slope and 7 represents the y intercept.

B= y= - $\frac{3}{2}$ x+ 6

- $\frac{3}{2}$ is the slop and 6 is the y intercept.

Hope this helps :)

8 0

2 years ago

When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam. They had 504 chocolates altogether. How m

IgorLugansk [536]

Answer:

315 chocolate

Step-by-step explanation:

Let Sam's chocolate be S

Let Clariss's chocolate be C

When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam.

This can be written as:

C = 5S

The sum of their chocolate is 504 i.e

S + C = 504

Now, let us determine the chocolate of Clarissa after receiving 105 chocolate from Sam. This can be obtained as follow:

S + C = 504

But: C = 5S

S + 5S = 504

6S = 504

Divide both side by 6

S = 504/6

S = 84.

C = 5S = 5 x 84 = 420

Therefore, Clarissa have 420 chocolate after receiving 105 chocolate from Sam.

Now, to know the amount of chocolate that Clarissa has at first, we simply subtract 105 from the present amount that Clarissa have. This is illustrated below:

Amount of chocolate that Clarissa has a first = 420 – 105 = 315

Therefore, Clarissa had 315 chocolate at first.

3 0

2 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

2 years ago

What is the answer NEED HELP ASAP<br><br> b-14=9 WHO ever answers gets 10 points

Naddik [55]

Answer:

b-14 = 9

b = 23

Step-by-step explanation:

Add 14 to 9 to get b alone.

4 0

2 years ago

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