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algol13
3 years ago
5

Sarah is 6 years older than Amy.

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0

Answer:

B.

Step-by-step explanation:

The problem has got to be addition.

The sentence "Sarah is 6 years older than Amy." does not include any hint of subtracting, or multiplying.

A hint of multiplying in a expression would be the word 'times', like "Brandon is 6 times the age of Emily" which eliminates D.

A hint of subtraction in an expression would be the word 'less', like "Brandon is 6 less the age of Emily." which eliminates A and C.

The word 'older' indicates addition, or adding, and if it would have been subtraction, the keyword would be 'younger' because you are subtracting their age, like 19 - 11. The same goes with B, but adding.

Finally, we now know that it is B because there is no other addition choice.

I hope this helped. Please correct me if I am wrong.

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What is the length of side a?
Bad White [126]

\huge \bf༆ Answer ༄

According to given figure, The Triangle BDC is a right angled Triangle (Angle D = 90°)

So, we can apply Pythagoras theorem to find the Side a (Hypotenuse)

Now, let's solve ~

  • \sf \: BD {}^{2}   + CD {}^{2} =   BC {}^{2}

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  • \sf16 + 9 =  {a}^{2}

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  • \sf \: a =  \sqrt{25}

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Therefore, Length of side a is 5 units ~

6 0
2 years ago
What fraction is larger 7/8 or 14/16
Bas_tet [7]
7*2=14 8*2=16 which is 14/16 so they are the same

3 0
3 years ago
So in numeric form what is 700,000+40,000+9000+200 and +50
WARRIOR [948]

Answer: 749,250

Step-by-step explanation:

700,000 + 40,000= 740,000.

9,000+200+50= 9,250.

740,000 + 9,250 = 740,250.

4 0
3 years ago
Read 2 more answers
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
A card is randomly selected from a standard
shepuryov [24]

Answer:

3 / 13

Step-by-step explanation:

Hello!

There are 52 cards in a deck with half being red and half being black. The question ask for when a black card is drawn so we divide the total by 2

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6/26 we can simplify this

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The answer is 3 / 13

Hope this helps!

8 0
3 years ago
Read 2 more answers
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