Can someone help with this question please

I need the answer and explain please and thank you.

Dafna11 [192]

Use cos sin and tan and looks up rules of cos sin tan and it will show you the rules and use those methods to plug into your equation

6 0

3 years ago

Read 2 more answers

Help me with this one

Artist 52 [7]

9514 1404 393

Answer:

"complete the square" to put in vertex form

Step-by-step explanation:

It may be helpful to consider the square of a binomial:

(x +a)² = x² +2ax +a²

The expression x² +x +1 is in the standard form of the expression on the right above. Comparing the coefficients of x, we see ...

2a = 1

a = 1/2

That means we can write ...

(x +1/2)² = x² +x +1/4

But we need x² +x +1, so we need to add 3/4 to the binomial square in order to make the expressions equal:

$x^2+x+1\\\\=(x^2+x+\frac{1}{4})+\frac{3}{4}\\\\=(x+\frac{1}{2})^2+\frac{3}{4}$

_____

Another way to consider this is ...

x² +bx +c

= x² +2(b/2)x +(b/2)² +c -(b/2)² . . . . . . rewrite bx, add and subtract (b/2)²*

= (x +b/2)² +(c -(b/2)²)

for b=1, c=1, this becomes ...

x² +x +1 = (x +1/2)² +(1 -(1/2)²)

= (x +1/2)² +3/4

_____

* This process, "rewrite bx, add and subtract (b/2)²," is called "completing the square"—especially when written as (x-h)² +k, a parabola with vertex (h, k).

5 0

2 years ago

Someone pls help me with this question

Degger [83]

Answer:

volume=0.000064 $m^{3}$

mass=0.5888kg

Step-by-step explanation:

4 0

2 years ago

Help I cannot figure this question out.

netineya [11]

Answer:

B. x = -1 ± i

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Standard Form: ax² + bx + c = 0
Factoring
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define

x² + 2x = -2

Step 2: Identify Variables

Rewrite Quadratic in Standard Form [Addition Property of Equality]: x² + 2x + 2 = 0
Break up Quadratic: a = 1, b = 2, c = 2

Step 3: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-2 \pm \sqrt{2^2-4(1)(2)}}{2(1)}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-2 \pm \sqrt{4-4(1)(2)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-2 \pm \sqrt{4-8}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-2 \pm \sqrt{-4}}{2}$
[√Radical] Factor: $\displaystyle x=\frac{-2 \pm \sqrt{-1}\sqrt{4}}{2}$
[√Radicals] Simplify: $\displaystyle x=\frac{-2 \pm 2i}{2}$
Factor: $\displaystyle x=\frac{2(-1 \pm i)}{2}$
Divide: $\displaystyle x = -1 \pm i$

3 0

3 years ago

Solve 50q-43=52q-81

ladessa [460]

Move the variables to one side and the constants to the other

50q - 43 = 52q - 81

50q (-52q) - 43 (+43) = 52q (-52q) - 81 (+43)

50q - 52q = -81 + 43

-2q = -38

isolate the q, divide -2 from both sides

-2q/-2 = -38/-2

q = -38/-2

q = 19

hope this helps

8 0

3 years ago

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