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lord [1]
3 years ago
5

A Negative b Zero c Positive d Undefined

Mathematics
1 answer:
aliya0001 [1]3 years ago
6 0
I believe that the answer is C. Positive
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Need the question answered asap
anygoal [31]

Step-by-step explanation:

First find the area of the rectangle with the variables.

(x + 5) \times x =  {x}^{2}  + 5x

Now the areas are equal, so we have to solve the equation

{x}^{2}  + 5x = 36 \\ x +  \sqrt{5x}  = 6 \\ 3.236x = 6 \\ x = 1.854

8 0
2 years ago
Find the difference- (ab+3a+7)- (-5ab-2)
coldgirl [10]
<span>(ab+3a+7)- (-5ab-2)
=</span><span>ab+ 3a+ 7+ 5ab + 2
=3a + 6ab + 9</span>
3 0
3 years ago
in the Sahara desert one day it was 136°F in the gobi desert a temperature of -50°F was recorded what is the difference between
Zolol [24]

Answer:

  186 °F

Step-by-step explanation:

The difference is found by subtracting the smaller from the larger:

  136 -(-50) = 136 +50 = 186

The difference between the two temperatures is 186 °F.

4 0
3 years ago
If postage costs $.54 for the first ounce and $.22 for the each additional ounce, calculate the cost of mailing a 10- ounce enve
sweet-ann [11.9K]

Answer:

Hence, the total cost of mailing 10 ounces is:

$ 2.52

Step-by-step explanation:

If postage costs $.54 for the first ounce and $.22 for the each additional ounce.

i.e. cost of first ounce=$ 0.54.

Now let x denote the number of ounces after the first ounce,

Hence, the cost of x ounces=$ (0.22×x)=$ 0.22 x

Hence, the cost of mailing (x+1) ounces is: $ (0.54+0.22 x)

Now, we have to find the cost of  mailing a 10- ounce envelope.

i.e. after the first ounce we need 9 more ounces.

Hence, the total cost of mailing is calculated as:

=$ (0.54+0.22\times 9)\\\\=$ (0.54+1.98)\\\\=$ 2.52\\

Hence, cost of mailing 10 ounces is:

$ 2.52

8 0
3 years ago
Read 2 more answers
20 POINTS PLEAE HELP!!!!!!!!!!!!!!!
Alina [70]
His first payment is $100, thus a₁ = 100.

the next "term", month will be 1.1 times more than the one before, namely r = 1.1, the common ratio.

\bf \qquad \qquad \textit{sum of a finite geometric sequence}&#10;\\\\&#10;S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=100\\&#10;r=1.1\\&#10;n=20&#10;\end{cases}

\bf \sum\limits_{i=1}^{20}~100(1.1)^{i-1}\qquad \qquad\qquad  \qquad S_{20}=100\left( \cfrac{1-1.1^{20}}{1-1.1} \right)&#10;\\\\\\&#10;S_{20}=100\left( \cfrac{1-\stackrel{\approx}{6.727499949}}{-0.1} \right)\implies S_{20}\approx 100(57.27499949)&#10;\\\\\\&#10;S_{20}\approx 5727.4999493256

is the serie divergent or convergent?

well, to make it short, when the common ratio is 0 < | r | < 1, namely a fraction between 0 and 1, only then the serie is convergent, namely it reaches a fixed value, now in this case, 1.1 is a value larger than anything between 0 and 1, so no dice.
5 0
3 years ago
Read 2 more answers
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