Question

solve 8x + 3y = 13 3x + 2y = 11 by using elimination. SHOW ALL WORK!! PLEASE HELP!!! THANK YOU SO MUCH!! :)))))

Answer 1

Hey There!

We have been given:

$8x + 3y = 13 \\ 3x + 2y = 11$

Find the lcm of 3 and 2 to eliminate one equation:

3 * 2 = 6

2 * 3 = 6

Multiply each equation to get to 6:

$2(8x + 3y = 13)\\ 16x + 6y = 26$

$3(3x + 2y = 11)\\ 9x+6y=33$

Eliminate:

$16x + 6y = 26\\ -(9x+6y=33)\\ -9x - 6y=-33$

Simplify:

$16x + 6y = 26\\ -9x - 6y=-33 \\ 7x = -7$

Solve for x by dividing 7 in both sides:

$7x = -7\\ x = -1$

Solve for y by substituting x in any equation with -1:

$8(-1) + 3y = 13$

Simplify:

$-8 + 3y = 13$

Add 8 in both sides:

$3y = 21$

Solve for y by dividing 3 in both sides:

$y = 7$

The value of x is -1 and the value of y is 7

Our answers:

x = -1

y = 7

Answer 2

Answer:Y=7

Step-by-step explanation:

-8x-3y = -13    (eq 1)

-3x-2y = -11    (eq 2)

First, multiply equation 1 by 2.

-16x-6y = -26

Second, multiply equation 2 by 3.

-9x-6y = -33

Subtract the system of equations:

-16x-6y = -26

-9x-6y = -33

-7x = 7

x = -1

Substitute this value into one of the original equations to solve for y

-3x-2y = -11

-3(-1)-2y = -11

3-2y = -11

-2y = -14

y = 7

Really hope this helps  :)