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3 years ago

Which lines are perpendicular to 7x-3y=18

Mathematics

1 answer:

inna [77]3 years ago

8 0

The answer is going to be 3y=7x-15. hope that helped

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What is the sum of 10/12and 11/12? Make sure to show all work to receive full credit!

sergiy2304 [10]

Answer:

$1\frac{3}{4}$

Step-by-step explanation:

$\frac{10}{12} +\frac{11}{12} \\\\\frac{21}{12} \\\\1\frac{9}{12} \\\\1\frac{3}{4}$

7 0

3 years ago

Wheel I has diameter 23.4. Wheel ll has diameter 18.0. Round the diameter of each wheel to the nearest inch. About how much fart

11111nata11111 [884]

Answer:

Wheel1 = 147inches , wheel 2 = 113inches

Wheel 1 will travel 147 revolutions.

Step-by-step explanation:

Finding the circumference of both wheels

Wheel 1 = 2 pi r = 2 × 3.142 × 23.4 = 147.05 inches. To the nearest inches = 147inches

Wheel 2 = 2 pi × r = 2 × 3.142 × 18 = 113.11inches . To the nearest inches = 113inches.

I rotation = 1 revolution

In 1 rotation, wheel 1 will travel= 147 × 1 = 147 revolutions.

8 0

3 years ago

Read 2 more answers

Evaluate cos0 if sin0= sqrt(5)/3 a. 9/5 b. 2/3 c. 5/9 d. 3/2

Evgesh-ka [11]

Solution given:

$\sin( \alpha ) = \frac{\sqrt{5} }{3}$

P=√5

h=3

b= $\sqrt{3 {}^{2} - \sqrt{5} {}^{2} }$

b=2

$\cos( \alpha ) = \frac{b}{h} = \frac{2}{3}$

Note

$\alpha = 0$

b:⅔

8 0

3 years ago

Rick has 1/2 of a footlong sub left from yesterday. He ate 1/3 of the leftover sandwich as a snack. What fraction of the entire

Lelechka [254]

The answer is 1/6 of the sandwich

8 0

3 years ago

Read 2 more answers

1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x

qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is $(2x+10)^\circ$ , so the measure of arc DF is

$m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ$

The inscribed angle theorem tells us that the central angle subtended by arc DF, $\angle DOF$ , has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

$m\angle DOF=2m\angle OEF=64^\circ$

so the measure of arc DF is also 64 degrees. So we have

$170-2x=64\implies106=2x\implies\boxed{x=53}$

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

$m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ$

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

$m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}$

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

$m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}$

7 0

3 years ago