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JulsSmile [24]
3 years ago
14

(I'LL GIVE BRAINLIEST)

Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0
1. 55.24
2. 13,000
3. 27x4=108

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Find the equation that models the path of a satellite if its path is a hyperbola, a=55,000 km and c=81,000 km. Assume the center
Yuki888 [10]

Given:

Hyperbola

a=55,000 km and c=81,000 km

hyperbola is the origin and the transverse axis is horizontal

Required:

Equation of the path of a satellite

Solution:

Formula for hyperbola, (x-h)2/a2 – (x-k)2/b2 = 1

At origin, (h, k) = (0, 0)

(x-0)2/(55000)2 – (x-0)2/(81000)2 = 1

<span>X2/12100 – y2/26244 = 250000</span>

8 0
3 years ago
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Explain the difference between a rate and a unit rate.
Anna35 [415]

Answer:

Step-by-step explanation:

A rate is a special ratio in which the two terms are in different units. For example, if a 12-ounce can of corn costs 69¢, the rate is 69¢ for 12 ounces. When rates are expressed as a quantity of 1, such as 2 feet per second or 5 miles per hour, they are called unit rates.

3 0
3 years ago
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The sum of two numbers is 150 and the ratio of the same two numbers is 3 to 2 . find the bigger number
krek1111 [17]
Ratio- 3: 2

3x + 2x = 150
5x = 150
x = 30

3x is the larger number so plug in the x value with 30.

3x
3 x 30
90

The larger number is 90.

Hope I helped.. ^^
8 0
3 years ago
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The cost of electricity in a certain city is $0.08 for each of the first 300kWh (kilowatt-hours) and $0.13 for each kilowatt-hou
Ivahew [28]

Step-by-step explanation:

0.08*300 + 0.13x = 51.95

Multiply thru by 100 to get:

8*300 + 13x = 5195

13x = 5195-2400

13x = 2,795

x = 215 hours

7 0
3 years ago
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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

7 0
3 years ago
Read 2 more answers
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