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Liono4ka [1.6K]
3 years ago
9

Write and solve an inequality for x.

Mathematics
2 answers:
maksim [4K]3 years ago
8 0

x + 2 > 5

x > 3

Answer is the 2nd option

x + 2 > 5; x > 3

Alex3 years ago
4 0

it is c im 100% sure

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What is a No solution? What is a infinite solution?
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No is a solid answer and infinite solution well that just means anything
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PLEASE HELP!! Using the SAS Congruence Theorem
Komok [63]

Answer:

SAS

Step-by-step explanation:

JK is congruent to LM   (given)

L is midpoint of JN (given)

JL is congruent to LN (definition of midpoint)

JK is parallel to LM (given)

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3 years ago
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An account grows at an annual interest rate of r⁡​ ⁣, so it grows by a factor of x=1+r⁡​ ⁣⁣ ​⁡ each year. The function A(x)=800x
Paladinen [302]

Given:

Annual interest rate = r⁡​%

Growth factor : x = 1 + r⁡​

The below function gives the amount in the account after 4 years when the growth factor is x⁡​ ⁣⁣.

A(x)=800x^4+350x^3+500x^2+600x

To find:

The total amount in the account if the interest rate for the account is 3% each year and initial amount.

Solution:

Rate of interest = 3% = 0.03

Growth factor : x = 1 + ⁡0.03 = 1.03

We have,

A(x)=800x^4+350x^3+500x^2+600x

Substitute x=1.03 in the given function, to find the total amount in the account if the interest rate for the account is 3% each year.

A(1.03)=800(1.03)^4+350(1.03)^3+500(1.03)^2+600(1.03)

A(1.03)=800(1.12550881)+350(1.092727)+500(1.0609
)+618

A(1.03)=900.407048+382.45445+530.45+618

A(1.03)=2431.311498


A(1.03)\approx 2431.31


Therefore, the total amount in the account is 2431.31 if the interest rate for the account is 3% each year.

For initial amount the rate of interest is 0.

Growth factor : x = 1 + ⁡0 = 1

Substitute x=0 in the given function to find the initial amount.

A(1)=800(1)^4+350(1)^3+500(1)^2+600(1)

A(1)=800+350+500+600

A(1)=2250

Therefore, 2250 was put into the account at the beginning.

3 0
3 years ago
Lee is staying at a hotel. The cost of the first night is $240. The cost for each night after that is $210. Let y represent the
GenaCL600 [577]

A) The situation represents an arithmetic sequence because the successive y-values have a common difference of 210.

F(1) = 240 +210

F(2) = 240 +2(210)

F(3) = 240+3(210)

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F(x)= 240 +210x.

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3 0
2 years ago
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
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