Given:
The point on the terminal side of theta is (4,-7).
To find:
The exact values of sin theta, secant theta, and tangent theta.
Solution:
If a point is on the terminal side of theta and , then
The point on the terminal side of theta is (4,-7). Here, and .
Now,
Therefore, .
Option A
The line is perpendicular to
<u>Solution:</u>
Given that line is
We have to find the line perpendicular to this line.
The given line equation is in form of slope-intercept form
<em><u>The slope-intercept form is given as:</u></em>
y = mx + c
Where "m" is the slope of the line and "c" is the y-intercept
On comparing the given equation with slope-intercept form, we get
<em>If a line is perpendicular to another line, then the product of their slopes will always be -1</em>
Let the slope of line which is perpendicular to given line be "a"
Then we get,
Now look at the options and compare with slope intercept form and find out which option has the slope "m" =
Option A has the slope
Thus option A is correct
Answer:
x=2
y=2
x=1.3 or 4/3
y=-4
Step-by-step explanation:
The error is in the first step. It should be (+8 plus or minus the square root of the quantity eight squared minus four times one times seven ). This is because "b" is -8 so -b is -(-8) = +8
-5x+4y=2
9x-4y=6
eliminate the 4y as a positive 4 + negative 4 =0
this will leave you with
-5x=2
9x=6
add them
4x=8
divide both sides by 4
x=2
to find y, plug in x=2 for any one of the original equations
-5(2)+4y=2
-10+4y=2
add 10 to both sides
4y=12
divide both sides by 4
y=3
the final answer is (2,3)