Answer:
no solution
Step-by-step explanation:
If first equation is divided by 2 and the second equation is divided by 3, we get two equations 2x+y=3 and 2x+y= 4. These two lines are parallel and there cannot be any solution to the system
Formula of surface area of cuboid = 2(lb+bh+lh) . Surface area of cuboid is 14800cm^2 (Given) then 14800 = 2(60*40+40*Height+Height*60) 14800= 2(2400+40*H+H*60) 14800= 4800+80*2H+2H*60 14800= 4880*4H*60 14800/4880*60= 4H
14800/292800=4H
7400/146400=4H
3700/73200=4H
1850/36600=4H
925/18300=4H
185/3660=4H
37/732=4H
37/732*4=H
37/2928=H
H= 79.1351351
6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5
2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
x = 12
so
m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41
answer
b. 41
7)
2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
x = 83
x + 14 = 83 + 14 = 97
2 angles are 83 and 97
answer
b. 83, 97
First, by using the distance formula for just one side, we can find the length of all sides (a square has 4 equal sides.) Then, we can apply the area of a square formula, which is a^2.
Distance formula:
√((-2 + 5)^2 + (-8 + 4)^2)
√((3)^2 + (4)^2)
√9 + 16
√25
5
The side lengths of the square are each equal to 5, and by applying the formula for area, we can find the area of the square.
5^2 = 25
<h3>The area is 25.</h3>