Simplify the following:
2^3 (4×36/12 + 1/4)
4×36/12 = (4×36)/12:
2^3 ((4×36)/12 + 1/4)
2^3 = 2×2^2:
2×2^2 ((4×36)/12 + 1/4)
2^2 = 4:
2×4 ((4×36)/12 + 1/4)
2×4 = 8:
8 ((4×36)/12 + 1/4)
36/12 = (12×3)/12 = 3:
8 (4×3 + 1/4)
4×3 = 12:
8 (12 + 1/4)
Put 1/4 + 12 over the common denominator 4. 1/4 + 12 = 1/4 + (4×12)/4:
8 1/4 + (4×12)/4
4×12 = 48:
8 (1/4 + 48/4)
1/4 + 48/4 = (1 + 48)/4:
8 (1 + 48)/4
1 + 48 = 49:
8×49/4
8×49/4 = (8×49)/4:
(8×49)/4
8/4 = (4×2)/4 = 2:
2×49
2×49 = 98:
Answer: 98
The discriminante :
b^2-4ac
1^2 - 4 * -2 * -28 = 1 - 224 = -223
When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.
-223<0, so, 2x^2+x-28 = 0 has no real solutions.
Hope that helps :)
7x - 1 + 6x - 1 = 180
add the x’s, add the numbers
13x - 2 = 180
add 2 to 180
13x = 182
divide 182 by 13
x = 14
