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erastova [34]
3 years ago
13

153.76 in expanded form

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0
100 + 50 + 3 + 7/10 + 6/100
dedylja [7]3 years ago
5 0
153.76 in expanded form is 100 + 50 + 3 + 0.7 + 0.06

We've expanded the number to show the value of each of its digits. When we expand a number to show the value of each digit, we're writing that number in expanded form.
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Write the equation of the line passing through points ( -2,-5) and (1,1)
Dennis_Churaev [7]

Answer:

The equation of the line is:

y=2x-1

Step-by-step explanation:

Given the points

  • (-2, -5)
  • (1, 1)

Finding the slope between the points

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-2,\:-5\right),\:\left(x_2,\:y_2\right)=\left(1,\:1\right)

m=\frac{1-\left(-5\right)}{1-\left(-2\right)}

m=2

We know the slope-intercept form of the line equation

y=mx+b

where m is the slope and b is the slope-intercept form

substituting the value m=2 and the point (-2, -5) to find the b-intercept

y=mx+b

-5 = 2(-2) + b

b = -5+4

b = -1

Now, substituting m=2 and b=-1 in the slope-intercept form to get the equation of a line

y=mx+b

y=2x+(-1)

y=2x-1

Thus, the equation of the line is:

y=2x-1

8 0
3 years ago
I don't understand! help please!!! ​
Lina20 [59]

Answer:

try leaving and coming back to it

Step-by-step explanation:

7 0
3 years ago
Help ASAP!!! Please show all work!!!!!!!
Anastaziya [24]

Answer:

x = 2 and x = -3

Step-by-step explanation:

We need to find the value of x in the below expression.

\sqrt{x+7} -1=x

Adding 1 to both sides,

\sqrt{x+7} -1+1=x+1\\\\\sqrt{x+7}=x+1

Squaring both sides,

x+7=(x+1)^2\\\\x+7=x^2+1+2x\\\\x^2+1+2x-x-7=0\\\\x^2+x-6=0\\\\x=2\ and\ -3

Hence, this is the required solution.

6 0
3 years ago
Read 2 more answers
A researcher is using a two-tailed hypothesis test with α = .05 to evaluate the effect of a treatment. If the boundaries for the
Solnce55 [7]

Answer:

A. ​n = 22

Step-by-step explanation:

Hello!

The researcher conducted a one-sample t-tas with the following hypotheses:

H₀: μ = μ₀

H₁: μ ≠ μ₀

α:0.05

The one-sample t-test has "n-1" degrees of freedom and since the hypotheses are two-tailed you know that the rejection region will be divided into two tails with "α/2" for each tail.  ± t_{n-1;1-\alpha /2}

If α:0.05 then α/2:0.025 and 1-α/2= 0.975

Using the given sample sizes as a reference you look in the table for the corresponding DF for an accumulated probability of 0.975

For n = 22 t_{21;0.975}= 2.080

For n= 21  t_{20;0.975}= 2.086

For n= 20 t_{19;0.975}= 2.093

The correct answer is a) n= 22

I hope this helps!

5 0
4 years ago
Two 6-sided dice are tossed. One die is red and the other is white, so that they are distinguishable. (That is, we consider the
Darina [25.2K]

Answer:

Given the following events and its elements when two 6-sided dice are tossed:

A: the sum of the dice is even

B: at least one die shows a 3

C: the sum of the dice is 7

The elements of the intersections are:

a) A∩B={(1, 3),(3, 1),(3, 3),(3, 5),(5, 3)}

b) B^c∩C={(1, 6),(2, 5),(5, 2),(6, 1)}

c) A∩C={∅}

d) A^c∩B^c∩C^c={(1, 2),(1, 4),(2, 1),(4, 1),(4, 5),(5, 4),(5, 6),(6, 5)}

Step-by-step explanation:

The total number of elements of the universal set (U) for this problem is 36 elements because the number of possible combinations is 6*6.  

For the event A, half of the elements satisfy the condition of the sum being an even number.

A={(1, 1),(1, 3),(1, 5),...,(6, 2),(6, 4),(6, 6)}=18 elements

For event B, the elements that contain a 3 are:

B={(1, 3),(2, 3),(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),

(4, 3),(5, 3),(6, 3)}= 11 elements

For event C, the sum of the elements is 7:

C={(1, 6),(2, 5),(3, 4),(4, 3),(5, 2),(6, 1)}=6 elements

Now let's find the intersections:

a) A∩B are the elements of A that have a 3.

A∩B={(1, 3),(3, 1),(3, 3),(3, 5),(5, 3)}

b) B^c∩C are the elements of the universal set (U) that do not have a 3 and that the sum of the dice is 7

B^c∩C={(1, 6),(2, 5),(5, 2),(6, 1)}

c) A∩C are the elements of that sum 7, but this is not possible given that all the elements of A sum an even number and 7 is not an even number.

A∩C={∅}

d) A^c∩B^c∩C^c are the elements that don't sum an even number, don't have a 3 and the sum is not 7.

A^c∩B^c∩C^c={(1, 2),(1, 4),(2, 1),(4, 1),(4, 5),(5, 4),(5, 6),(6, 5)}

5 0
3 years ago
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