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zhenek [66]
3 years ago
9

Describe the geometric meaning of the following mappings in spherical coordinates.

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0

Answer:

A. (iv)-There is a rotation by π around the x-axis.

B. (v)-There is a reflection across the xy plane.

C. None of the above, There is a rotation by π/2 about the x-axis with a radial expansion by a factor of 2.

Step-by-step explanation:

A. In spherical coordinates, for some point in R³, the angle θ is designed to be the angle between the x-axis and the projection of the line that goes from (0,0,0) to that point into the xy plane.

So, if you add π to the angle it only rotate 180 degrees or π units about the x-axis

B.  In spherical coordinates, for some point in R³, the angle ϕ is designed to be the angle between the z-axis and the diagonal from (0,0,0) to that point.

So, if you subtract π to the angle it would flip the diagonal in the negative part of z (assuming ϕ<π/2, otherwise, originally the diagonal would be in the negative part of z and it would flip to the positive part of z) and this could be interpreted as a reflection around the xy plane. Notice if ϕ=π/2, then π − ϕ=π/2 so everything stays the same for points that belong to xy plane (i.e that ϕ=π/2)

C.  In spherical coordinates, for some point in R³, ρ is designed to be the length of the diagonal from (0,0,0) to that point. So if we multiply ρ by 2, we are expanding the length of the diagonal.

But as we´ve seen before, adding something to θ means a rotation about x-axis by what we are adding (π/2)

Then the answer is that there is a rotation by π/2 about the x-axis with a radial expansion by a factor of 2.

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Suppose 2 eggs with bacon cost 2.70 . One egg with bacon costs 1.80 . At thesebrates what will bacon alone cost
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3 years ago
Heart failure is due to either natural occurrences (89%) or outside factors (11%). Outside factors are related to induced substa
Firdavs [7]

Answer:

a) 11% probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors.

b) 0.0871 = 8.71% probability that third patient with heart failure that enters the emergency room is the first one due to outside factors.

c) The mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors is 9.09.

Step-by-step explanation:

We have these following probabilities:

89% probability that a patient has heart failure due to natural occurrences.

11% probability that a patient has heart failure due to outside factors.

A) What is the probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors?

We assume that causes of heart failure between individuals are independent, which means that the probabilities are the same for each patient. So:

11% probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors.

B) What is the probability that third patient with heart failure that enters the emergency room is the first one due to outside factors?

First two due to natural occurrences, each with 89% = 0.89 probability.

Third due to outside factors, with 11% = 0.11 probability. So

0.89*0.89*0.11 = 0.0871

0.0871 = 8.71% probability that third patient with heart failure that enters the emergency room is the first one due to outside factors.

C) What is the mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors?

11% with outside factors, so the mean number of patients before the first with outside factors is given by

m = 1/0.11 = 9.09

The mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors is 9.09.

4 0
3 years ago
Can you help me find my mistake
Hunter-Best [27]
Sorry i dont know im not that far in school that's like high school stuff sorry


8 0
3 years ago
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