Answer:
p(s) = 0,33
Step-by-step explanation:
n = 450
p₀ = 150/450 p₀ = 0,33 then q₀ = 0,67
n*p₀ = 0,33*450 = 150
n*q₀ = 0,67*450 = 301
n*p₀ and n*q₀ more than 10, we can approximate the binomial to a Normal Distribution Distribution
a) p - p₀ = z(c) * √ (p₀q₀)/n
z(c) = ??
CI 95 % then α = 5 % α = 0,05 α/2 = 0,025
z(c) = 1,96
p = p₀ ± z(c) * √ (p₀q₀)/n
p = 0,33 ± 1,96 * 0,022
p = ( 0,33 - 0,04 ; 0,33 + 0,04
p = ( 0,29 ; 0,37 )
The value of the center of the confidence Interval is 0,33
p(s) = 0,33
Hi,
Answer: B) 25.82%
<u>My work:</u> For this problem you can easily achieve this problem (Preferably with a caculator) by taking the date’s 2014 and 1969 the time of growth and subtract them. When you do this you get the answer 45. From there you you take 45 (With caculator) and multiply it with 25.82 % (To do this you take 25.82 and press 2nd, then the percent). When you do this you get 11.619 which rounded is 12; furthermore, which is your answer.
I Hope I Helped!
9.75 millimeters = 0.975 centimeters
The intrusions are there on the paper read it 3 times
Let me see if 57.3 is correct I’m not sure tho does it give you options?
