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LenKa [72]
3 years ago
7

Which of the following could be an equation of the line that is perpendicular to= 2x + 5

Mathematics
2 answers:
nataly862011 [7]3 years ago
8 0
Alright, I don't know what your choices are, but here's my input:
For a line to be perpendicular to another line, the slope needs to be the opposite reciprocal of the slope of the given line. Now, by opposite, I mean if your slope is positive, this one needs to be negative (or vice versa). For reciprocal, I mean flip the fraction over. In this case, we have a slope of 2, so its opposite is -2 & the reciprocal is -1/2. So, whatever line has a slope of -1/2 is your answer.

Hope this helps!
vaieri [72.5K]3 years ago
3 0
I say that it is line x+3
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[(7**13)**3]*[7**0]

[7**39]*[1]..........>   9.0954 E 32 Strawberries in the field
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Which fraction has the greatest value 1/3 2/3 2/9 2/9
sdas [7]
2/3 has the greatest Value 



3 0
3 years ago
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A firework is launched at the rate of 10 feet per second from a point on the ground 50 feet from an observer. to 2 decimal place
Kazeer [188]

The rate of change of the angle of elevation when the firework is 40 feet above the ground is 0.12 radians/second.

First we will draw a right angle triangle ΔABC, where ∠B = 90°

Lets, assume the height(AB) = h and base(BC)= x

If the angle of elevation, ∠ACB = α, then

tan(α) = \frac{AB}{BC} = \frac{h}{x}

Taking inverse trigonometric function, α = tan⁻¹ (\frac{h}{x}) .............(1)

As we need to find the rate of change of the angle of elevation, so we will differentiate both sides of equation (1) with respect to time (t) :

\frac{d\alpha}{dt}=[\frac{1}{1+ \frac{h^2}{x^2}}]*(\frac{1}{x})\frac{dh}{dt}

Here, the firework is launched from point B at the rate of 10 feet/second and when it is 40 feet above the ground it reaches point A,

that means h = 40 feet and \frac{dh}{dt} = 10 feet/second.

C is the observer's position which is 50 feet away from the point B, so x = 50 feet.

\frac{d\alpha}{dt}= [\frac{1}{1+ \frac{40^2}{50^2}}] *\frac{1}{50} *10\\ \\ \frac{d\alpha}{dt} = [\frac{1}{1+\frac{16}{25}}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt} = [\frac{25}{41}] *\frac{1}{5}\\   \\ \frac{d\alpha}{dt}= \frac{5}{41} =0.1219512

= 0.12 (Rounding up to two decimal places)

So, the rate of change of the angle of elevation is 0.12 radians/second.

5 0
3 years ago
Just the last two ones please and thank you if you awnsered this
Rudik [331]
Number 1 is twenty and number two is fifty six
8 0
3 years ago
Please help idk thisssss
Alekssandra [29.7K]
ANSWER
0.073 \% = 0.00073


EXPLANATION

Recall that,

\% =  \frac{1}{100}


That is why
100\%
is equivalent to
1.





This implies that,


0.073\% = 0.073 \times  \frac{1}{100}






This is the same as,


0.073\% = \frac{0.073}{100}


When we are dividing by
100
we move the decimal point backwards two times.


This implies that,

0.073\% = 0.00073


6 0
3 years ago
Read 2 more answers
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