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a_sh-v [17]
3 years ago
11

Nancy bought 360 tropical fish for a museum display. She bought 8 times as many gold fish as angel fish. How many of each type o

f fish did she buy?
Which is a system of equation to model the problem if x represents the number of angel fish Nancy bought and y represents the number of gold fish she bought?

a) x - y = 360
y = 8x

b) x + y = 360
y = 8x

c) x + y = 8
y = 360x

d) x + 8y = 360
y = 8x
Mathematics
2 answers:
Maru [420]3 years ago
8 0
The answer is b.
if you think about it, the details say that she bought 360 fish, 8 times more than goldfish than angel fish. if the gold fish were x, and the angle fish were y, it would be x+y=360 with y=8x. it is addition because the TOTAL is a combination of angel fish and gold fish. you aren't subtracting anything.
12345 [234]3 years ago
3 0
I think the answer is C.
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Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: (\frac{n+1}{2}) th\ term

Putting n=21

(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

<u>For First Half:</u>

98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132

Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5

<u>For Second Half:</u>

135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151

Now

<u>Interquartile Range:</u>

IQR = Q_3-Q_1\\= 151-108.5\\=42.5

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrianly

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