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Zanzabum
3 years ago
11

A box with no top is to be constructed from a piece of cardboard whose length measures 88 in. more than its width. the box is to

be formed by cutting squares that measure 33 in. on each side from the four corners and then folding up the sides. if the volume of the box will be 144144 in.cubed3​, what are the dimensions of the piece of​ cardboard?
Mathematics
1 answer:
MariettaO [177]3 years ago
4 0

Let x be the width of the cardboard (which means the length of the cardboard is x+88), then the dimensions of the box are:

Length = [(x + 88) - 2(33)]

Width = x - 2(33)

Heighth = 33

Volume = length · width · heighth

144,144 = [(x + 88) - 2(33)] · [x - 2(33)] · 33

144,144 = (x+22)(x-66)(33)

4368 = (x+22)(x-66)

4368 = x² - 44x - 1452

0 = x² - 44x - 5820

use the quadratic formula to calculate that x = 101

Answer: cardboard width = 101, cardboard length = 189

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Answer:

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If g(x) = 4x^2 - 16 were shifted 7 units to the right and 3 down, what would the
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Answer:

The new equation is h(x)=4(x-7)^2-19

Step-by-step explanation:

Given : Function g(x) = 4x^2 - 16 were shifted 7 units to the right and 3 down.

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Solution :

Shifting to the right with 'a' unit is

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So, shifting g(x) 7 units to the right is

h(x) = 4(x-7)^2-16

Shifting to the down with 'b' unit is

f(x)→f(x)-b

So, shifting g(x) 3 units down is

h(x)=(4(x-7)^2-16)-3

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The new equation is h(x)=4(x-7)^2-19

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3 years ago
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so
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an=40+7(n-1)
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the domain is natural numbers because you can't have the -3rd term or the 0th term or the 3.24th term

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