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padilas [110]
3 years ago
8

Number

Mathematics
1 answer:
DerKrebs [107]3 years ago
8 0

Answer:a=1/5

B=2/15

Step-by-step explanation:

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The runic cube company packages its 1/4ft, cubes in boxes that are 1 1/2 ft by 1ft by 3/4 ft. How many Rubio cubes can the compa
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4. In the evenings, Jake and his friends would cook out and make smores for dessert. The ratio
lorasvet [3.4K]

Answer:

A. y = 3/2x

B. you need 3 chocolate squares and 2 graham crackers to make 1 smore

C. 0, 0 chocolate squares and 0 graham crackers make 0 smores

Step-by-step explanation:

A. rise/run = 3/2

B. slope = 3/2

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An average male Asian elephant grows to about three meters at the shoulders. What is the average height in centimeters?
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300 centimeters

Step-by-step explanation:

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A car can travel 24 miles for every 1 gallon of gasoline.
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3 years ago
Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
3 years ago
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