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3 years ago

Number

Mathematics

1 answer:

DerKrebs [107]3 years ago

8 0

Answer:a=1/5

B=2/15

Step-by-step explanation:

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The runic cube company packages its 1/4ft, cubes in boxes that are 1 1/2 ft by 1ft by 3/4 ft. How many Rubio cubes can the compa

Rainbow [258]

1/4+1 1/2+3/4=2.5
hope this helps!!!!!

3 0

3 years ago

Read 2 more answers

4. In the evenings, Jake and his friends would cook out and make smores for dessert. The ratio

lorasvet [3.4K]

Answer:

A. y = 3/2x

B. you need 3 chocolate squares and 2 graham crackers to make 1 smore

C. 0, 0 chocolate squares and 0 graham crackers make 0 smores

Step-by-step explanation:

A. rise/run = 3/2

B. slope = 3/2

3 0

3 years ago

An average male Asian elephant grows to about three meters at the shoulders. What is the average height in centimeters?

Jlenok [28]

Answer:

300 centimeters

Step-by-step explanation:

1 meter is equal to 100 cm so 3 x 100 = 300

4 0

3 years ago

A car can travel 24 miles for every 1 gallon of gasoline.

jasenka [17]

The car can travel 235.2 miles on 9.8 gallons. Just multiply 24 by 9.8.

5 0

3 years ago

Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

$g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}$

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

$x-1\leq 0\Rightarrow x\leq 1$

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0

4 years ago