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Ahat [919]
3 years ago
9

Two numbers total 63 and have a difference of 31. Find the two numbers

Mathematics
2 answers:
Anastaziya [24]3 years ago
5 0

Answer: 47 and 16

Step-by-step explanation:

- Make Two Equations

x + y = 63

x - y = 31

- Set one of the equations equal to one of the variables

x + y = 63

x = 31 + y

- Substitute the equation back into the other one

(31 + y) + y = 63

31 + 2y = 63

2y = 32

y = 16

- Substitute the answer back into the equation

x + y = 63

x + 16 = 63

x = 47

Dominik [7]3 years ago
4 0

Answer:

47 and 16

Step-by-step explanation:

Start by writing this question as two equations, lets call the two numbers x and y.

"Two numbers total 63" we can write that as x+y=63

"...and have a difference of 31" we can write that as x-y=31 or y-x=31 or |x-y| = 31 or |y-x| = 31. There a lot of ways to write that.

So lets use y-x=31 as the second equation, you can ignore the other possible ways since it doesn't matter in this problem to use absolute value

Using subsitution solve for x using x+y = 63,  x = -y + 63

Plug that into the other equation, -y+63-y=31

−2y+63=31 (Simplify both sides of the equation)

−2y+63+−63=31+−63 (Add -63 to both sides)

−2y=−32

y=16 (Divide both sides by -2 to get Y by itself)

We solved for Y(of of the numbers), now for X (the other number)

Substitute 16 for y in x= − y + 63:

x=−y+63

x=−16+63

x=47

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In a list of five consecutive odd integers, the sum of the first and double the last is 139. What is the largest sum?
Leviafan [203]

Answer: 49

Step-by-step explanation:

From your question, I think you mean the largest number. The answer is given below.

Let the five consecutive odd numbers be:

a, a+2, a+4, a+6 and a+8.

Thee sum of the first and double the last is 139. This can be written as:

a + 2(a+8) = 139

a + 2a + 16 = 139

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3a = 139 - 16

3a = 123

a = 123/3

a = 41

The first number = 41

The largest number = a+8 = 41 + 8 = 49.

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3 years ago
A detective has interviewed four witnesses to a crime. From the stories of the witnesses the detective has concluded
SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

Step 1:we should turn the “facts” into logical expressions.

Step 2:Assign variables

Our variables are: b (for butler), c (for cook), g (for gardener), h (for handyman)

Step 3 . Let the value of true indicate that the person is telling the truth. For example, b = T means the butler is telling the truth. Then we can translate the statements as follows:

Check attachment

Step 4

We know all of these must hold. So we really want to know when (b→c)∧¬(c∧g)∧¬(¬g∧¬h)∧(h → ¬c) is true.

Step 5

Behold, another truth table task! If you work out the truth table, you see that this statement is only true when:

Check attachment

Step 6

Therefore we can say the butler and cook are definitely lying, but we can not determine if the gardener or handyman are lying. However, there are four variables in this problem. Instead, we can do this with some straight reasoning. Notice that:

If the butler is telling the truth, then by (a) the cook is telling the truth.

If the cook is telling the truth, then by (b) the gardener is lying.

If the gardener is lying, then by (c) the handyman is telling the truth.

If the handyman is telling the truth, they by (d) the cook is lying.

This leads to a contradiction (the cook can not be both telling the truth and lying)! Therefore the butler and cook must be lying. What about the gardener and the handyman? We don’t have enough information to figure out if they are lying. Since the cook is lying, we can’t use (b) to come to any conclusions about the gardener. Even if we are able to conclude that the gardener is telling the truth, we can’t use (c) to come to any conclusions about the handyman.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Since the trapezium given in the problem satisfies those conditions, we use the formula with:

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