I hope this might be able to help you.
Since the value of the car slowly decreases each year and each year is represented by <em>y</em>, the function is 24,000-1750y=f(x).
1= 4/4 therefore 2=8/4
8/4 + 1/4 = 9/4
So Steve bought 9/4 of pizza total
Answer:
![\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EExponential%20Rules%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5Dx%5E%7Ba%7D%20%2B%20x%5E%7Bb%7D%20%3D%20x%5E%7Ba%20%2B%20b%7D)
![\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} } = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5Bb%5D%7Bx%5E%7Ba%7D%20%7D%20%3Dx%5E%7B%5Cfrac%7Ba%7D%7Bb%7D%20%7D%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EOriginal%20Equation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%20%20%3D%20x%5E%7B%5Cfrac%7B10%7D%7B3%7D%20%7D%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EAnswer%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3EConvert%20the%20cubed%20root%20to%20a%20power.%20Cubed%20root%20%3D%20%5Btex%5D%5Cfrac%7B1%7D%7B3%7D)

Convert them, so they have a common denominator - 


[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]
Answer: The correct answer is: " 3 " .
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Step-by-step explanation:
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The problem given is:
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Evaluate: log 2 base 8 .
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Rewrite as: "
" ; 
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Take note of the following definition of a logarithm:
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"
" ; ↔ "
" ;
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in which:
refers to the "base" ;
refers to the "argument" ;
refers to the "exponent" ;
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As such:
"
"
⇔ "
" ; Solve for "x" ;
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Note:
2⁰ = 1 ;
2¹ = 2 ;
2² = 2 * 2 = 4 ;
2³ = 2 * 2 * 2 = 8 .
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→ "
" ;
→ "
" ; since: "
" ;
→ as such: " x = 3 " ;
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Thus:
"log 2 base 8 " ;
=
.
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Hope this helps!
Best wishes to you!
A. Always
These lines<span> are </span>perpendicular<span> since their slopes are negative reciprocals.</span>