I'm doing the same thing right now and I'm lost.
Given:
The limit problem is:
![\lim_{x\to -\infty}(-2x^5-3x+1)](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%20-%5Cinfty%7D%28-2x%5E5-3x%2B1%29)
To find:
The value of the given limit problem.
Solution:
We have,
![\lim_{x\to -\infty}(-2x^5-3x+1)](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%20-%5Cinfty%7D%28-2x%5E5-3x%2B1%29)
In the function
, the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.
So, the function approaches to positive infinity as x approaches to negative infinity.
![\lim_{x\to -\infty}(-2x^5-3x+1)=\infty](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%20-%5Cinfty%7D%28-2x%5E5-3x%2B1%29%3D%5Cinfty)
Therefore,
.
1. (5+23)+65 = (5+65)+23 = 70+23 = 93 (D)
2. -(4x-7) = -4X+7 (C)
3. 2(6X+9) = 12X+18 (B)
4. 5(X-3) = 35
X-3 = 35/5
X-3 = 7
SO X= 7+3 = 10
THEN NO
9 IS NOT A SOLUTION
Answer:
qwertiopadfghkklzcvbnmweyiosghklsghksfjkerui
Answer:
2/3
Step-by-step explanation:
3y = 2x
Divide each side by 3
3y/3 = 2x/3
y = 2/3 x
The direct variation relationship is
y = kx
In this case k = 2/3