If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
27 (circumference) ➗ 3.14 (pi) = 8.59 (diameter)
Distance across (diameter) would be closest to 9.
you would add 3y+5y and get 8y=-20
then the slope would be 8/1 and your y-intercept would be -20
