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WINSTONCH [101]
3 years ago
5

Question 2 (Essay Worth 10 points) (03.05 HC) The table below represents the velocity of a car as a function of time: Time (hour

) x Velocity (miles/hours) y 0 50 1 52 2 54 3 56 Part A: What is the y-intercept of the function, and what does this tell you about the car? (4 points) Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. (4 points) Part C: What would be the domain of the function if the velocity of the car was measured until it reached 60 miles/hour and the car does not change motion? (2 points)
Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0
The y-intercept of the function is +5. The average rate is 1/3. The domain is 20.4 miles/hour.
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Rama09 [41]

Expanded form:

1 × 100,000,000
+ 5 × 10,000,000
+ 4 × 1,000,000
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+ 9 × 10,000
+ 8 × 1,000
+ 1 × 100
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I hope it helps :)
4 0
3 years ago
Help please, I need it
Helen [10]

Partial Answer:

For #10 the solutions are 2 and 5

Step-by-step explanation:

Solutions for an equation can be x-intercepts, or where it touches the x or horizontal line. The equation in #10 touches the x line at 2 and 5.

5 0
2 years ago
9x10^7 is how many times as large as 3x10^-2
lianna [129]

Answer:

3000000000 times bigger

Step-by-step explanation:

5 0
3 years ago
If x+y=8 and xy =15 find the value of x³+y³.​
alexgriva [62]

Answer:

<h2>152</h2>

Step-by-step explanation:

<h3>let x= 5 and y= 3</h3><h3 /><h3>x + y = 8</h3><h3>5 + 3 = 8</h3><h3 /><h3>xy = 15</h3><h3>5 × 3 = 15</h3><h3 /><h3>x³ + y³ = ?</h3><h3>5³ + 3³ = ?</h3><h3>125 + 27 = 152</h3>

\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}

7 0
3 years ago
Paws at play made a total of $1,234 grooming 22 dogs. Paws at play charges $43 to groom each small dog and $75 for each large do
Nesterboy [21]

Answer:

The system of equation can be used for determine the number of small and the large dogs groomed are

x + y = 22

43x + 75y = 1234

Step-by-step explanation:

Let us assume that the number of small dogs groomed be x.

Let us assume that the number of lagre dogs groomed be y.

As given

Paws at play made a total of $1,234 grooming 22 dogs.

Than the equation becomes

x + y = 22

Paws at play charges $43 to groom each small dog and $75 for each large dog.

Than the equation becomes

43x + 75y = 1234

Therefore the system of equation can be used for determine the number of small and the large dogs groomed are

x + y = 22

43x + 75y = 1234


4 0
3 years ago
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