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Montano1993 [528]
3 years ago
11

You have an office building that is 600 square feet in area. What are two possible dimensions how your office could be construct

ed?
Mathematics
1 answer:
stepan [7]3 years ago
8 0

Answer:

20\ ft  by  30\ ft

15\ ft  by  40\ ft

Step-by-step explanation:

In this problem I'm assuming the office is rectangular.

so

The area of rectangle is equal to

A=LW

where

L is the length of the rectangle

W is the width of the rectangle

In this problem we have

A=600\ ft^{2}

so

600=LW ------> equation A

Find two possible dimensions of the office

case A) Assume  a length side L and find the value of W in the equation A

so

For L=30\ ft

substitute in the equation and solve for W

600=(30)W

W=600/30=20\ ft

The dimensions are 20\ ft  by  30\ ft

case B) Assume  a length side L and find the value of W in the equation A

so

For L=40\ ft

substitute in the equation and solve for W

600=(40)W

W=600/40=15\ ft

The dimensions are 15\ ft  by  40\ ft

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