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NeX [460]
3 years ago
11

Multiple the following:(x2+4x-3)(x2-6x+7)

Mathematics
1 answer:
Katena32 [7]3 years ago
5 0

Answer:

=x^4−2x^3−20x^2+46x−21

if you can give me brainliest that would be great :)

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The probability distribution for a
Bumek [7]

Answer:

0.50

Step-by-step explanation:

X ___ - 5 ___ 3 __ - 2 __ 0 __ 12 __ 3

P(x) __0.17_0.13_0.33 _0.16 _0.11 _0.10

P(x <0) = p(x = - 2) + p(x = - 5)

P(x < 0) = 0.33 + 0.17

P(x < 0) = 0.50

5 0
3 years ago
Order the lengths of the sides of triangle ABC from greatest to least Angle A = 78° angle B = 56° and angle C = 46°
Fittoniya [83]

Answer:

AC ; BC ; AB

Step-by-step explanation:

Given the triangle attached :

Using visual cue, we can detect the and order the length of the sides of the triangle from greatest to least as follows :

Greatest = AC

Followed by BC ;

Then ; AB

Hence. We have ;

AC ; BC ; AB

3 0
3 years ago
Can someone help me , with math thanks
serious [3.7K]

Answer:

2+w greater than 5

Step-by-step explanation:

w=-3

3 0
3 years ago
Read 2 more answers
The graph of (x), shown below, is a vertical shift of the graph of f(x) = 3*
Deffense [45]
The Best Option is B
4 0
3 years ago
Jeff is standing on top of a tree next to a mysterious monolith (a big rectangular box). At time t = 0, Jeff threw a coconut ver
zimovet [89]

Answer:

h=\frac{h_{m}-h_{t}+44.145}{3}t-4.905t^{2}+h_{t}

(if the heights are measured in meters)

Step-by-step explanation:

In order to solve this problem we will need to first draw a diagram of the situation (see attached picture) and then, make use of the following physics equation:

y_{f}=\frac{1}{2}at^{2}+v_{0}t+y_{0}

where:

y_{f}=height of the object at a given time t

a=acceleration due to gravity

t=time

v_{0}=initial velocity of the object

y_{0}=initial height of the object.

we know most of this data, except for the height of theh object at the given time t and the initial velocity of theh object. We can make use of the given time to write the velocity in terms of the height of thte tree and the height of the monolith.

So let's substitute the values we know so far:

h=\frac{1}{2}(-9.81)t^{2}+v_{0}t+h_{tree}

the problem tells us that after 3 seconds, the object reaches the height of the monolith, so let's do the substitution:

h_{monolith}=\frac{1}{2}(-9.81)(3)^{2}+v_{0}(3)+h_{tree}

we can now solve this equation for the initial velocity, so we get:

h_{monolith}-h_{tree}=-44.145+3v_{0}

h_{monolith}-h_{tree}+44.145=3v_{0}

so:

v_{0}=\frac{h_{monolith}-h_{tree}+44.145}{3}

and now we can substitute this back into the original formula to get the equation that represents the height of the coconut above the ground after t seconds:

h=\frac{h_{m}-h_{t}+44.145}{3}t-4.905t^{2}+h_{t}

3 0
3 years ago
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