12 more than the product of a number and four is fewer than 60 write it in a algebraic inequality
1 answer:
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The first term is a(1) = -3
The recursive step is a(n) = a(n-1)+7 meaning "add 7 to each previous term to get the next term". This points us to the common difference d being 7
a1 = -3
d = 7
an = a1 + d(n-1)
an = -3 + 7(n-1)
an = -3+7n-7
an = 7n-10
Answer:
(it says an = 7n-10 if the image doesn't show up)
Note: the n starts at n = 1
The recursive step is a(n) = a(n-1)+7 meaning "add 7 to each previous term to get the next term". This points us to the common difference d being 7
a1 = -3
d = 7
an = a1 + d(n-1)
an = -3 + 7(n-1)
an = -3+7n-7
an = 7n-10
Answer:
Note: the n starts at n = 1