3 are expected to have the condition.
The expected value is the found by multiplying the probability by the number in the sample:
(1/200)×600
= (1/200)×(600/1)
= (1×600)/(200×1)
= 600/200 = 3
1/a
The b^-3 in the denominator and numerator cancel out
Answer:
2 and 3
Step-by-step explanation:
So, 24=2x2x2x3
42=2x3x7
3 and 2
