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RoseWind [281]
3 years ago
13

You work at a job and earn 58,000 annually. You work 222 days annually, 8 hours, daily. What is the day rate for your wage? What

is the per minute wage rate?
Mathematics
1 answer:
jeka943 years ago
8 0

Hello!

Hello!

First of all, let's divide into how much you earn each day.

58,000/222≈261.26

Now we divide by 8 to find per hour.

261.26/8≈32.66

Now we divide by 60 to find per minute.

32.66/60≈0.54

Therefore,they receive $261.26 day wage and $0.54 minute wage.

I hope this helps!

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I
krok68 [10]
Here you go mate. Very easy concept to learn :D good luck in your studies

5 0
3 years ago
The attendance at Southview High School's seven home football games was as follows: 575, 630, 720, 575, 525, 623, and 692. What
Nutka1998 [239]
Mode=most
1) order the numbers from least to greatest
   525,575,575,623,630,and 692
2)Any number that is repeated it is the mode if there is no number repeated there is no mode.
3)575 is repeated the most so that is your mode

Hope It Helps!

^o^
7 0
3 years ago
Brian has $78 and wants to purchase tapes through a music club. Each tape costs $7.50. The music club will add a total postage a
kramer

Answer:

9 tapes

Step-by-step explanation:

First, subtract the handling charge from his $78.

78 - 3.50 = 74.5

So, Brian has $74.50 to purchase tapes. Each tape costs $7.50, so let's find out how many he can purchase.

74.50 / 7.50 = 9.933 (approximately)

Since Brian can't buy 0.933 of a tape, he will only be able to buy 9 tapes.

7 0
4 years ago
If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's ru
aleksandrvk [35]

Answer:

Step-by-step explanation:

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's rule to compute the limit of the sequence given by

bn=(n)^(5.6/n).

a)

L =  \lim_{n \to \infty} b_n \\\\\\L= \lim_{n \to \infty} n^{\frac{5.6}{n} }

Log on both sides

In (L) =  \lim_{n \to \infty} In (n)^{\frac{5.6}{n} }\\\\= \lim_{n \to \infty} \frac{5.6}{n} In(n)

=5.6 \lim_{n \to \infty} \frac{d}{dn}  In(n)/\frac{d}{dn} (n)\\\\=5.6 \lim_{n \to \infty} \frac{1}{n} /1 \\\\=5.6 \lim_{n \to \infty} \frac{1}{n} \\\\=5.6 \times 0\\\\In(L) =0\\\\L=e^0\\\\L=1

\therefore  \lim_{n \to \infty} (n)^{\frac{5.6}{n} =1

5 0
3 years ago
PLEASE ANSWERR ILL OFFER BRAINILIEST
Illusion [34]

Answer:

its A

Step-by-step explanation:

if 20 is my 100 percent and I look for 70 percent it is the rule of 3. 20 x 70 between 100 = 34 Hope this helps

3 0
3 years ago
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