Answer:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:(7,6)
Equation Form: x=7, y=6
Answer:
Option (3)
Step-by-step explanation:
Explicit formula of the sequence is,

From this explicit formula,
First term of the sequence will be,


Second term of the sequence,

= 13
3rd term of the sequence,

= 31
Sequence formed,
7, 13, 31 ..........
From the given options,
Recursive formula,



= 13



= 39 - 8
= 31
Sequence formed from this recursive formula will be,
7, 13, 31........
Therefore, Option (3) will be the answer.

$\implies 2^{2x}-2\cdot5^{2x}-(2^x)(5^x)>0$
let $2^x=a$ and $5^x=b$
So, $a^2-2b^2-ab>0$
divide by $b^2$, ($b^2>0$)
$\implies \left(\frac ab\right)^2-\left(\frac ab\right) -2>0$
this is a quadratic, in $\left(\frac ab\right)$, let it be $x$
So, $x^2-x-2>0$
Can you simplify it now?
Answer:
15
x
+
10
y
Factor
5
out of
15
x
.
5
(
3
x
)
+
10
y
Factor
5
out of
10
y
.
5
(
3
x
)
+
5
(
2
y
)
Factor
5
out of
5
(
3
x
)
+
5
(
2
y
)
.
5
(
3
x
+
2
y
)
Step-by-step explanation:
Blue is more likely to appear then red