All categories

2 years ago

The area of a parallelogram is 120 cm ^ 2 and the height is 30 cm . Find the corresponding base

Mathematics

1 answer:

const2013 [10]2 years ago

3 0

Answer:

4 cm

Step-by-step explanation:

The Area of a parallelogram is given by :

Area = base * height

Area = 120 cm² ; height = 30

Area = base * height

120 = base * 30

Base = 120 / 30

Base of parallelogram = 4 cm

You might be interested in

What is the answer to -7=-21-×/4

NikAS [45]

Answer:

Step-by-step explanation:

Put the numbers in order from least to greatest:

5, 0, |-1|, |4|, -2

3 0

3 years ago

How do you find the slope of ordered pairs

DerKrebs [107]

Answer:

the slope is defined as the change in price divided by the change in quantity supplied between two points (i.e. the two ordered pairs). we can use the following formula to calculate it: m = (y2 – y1)/(x2 – x1). in the case of my example, the two ordered pairs are (2, 500) and (1, 250)

Step-by-step explanation:

7 0

3 years ago

Graph the line by locating any two ordered pairs that satisfy the equation y = 1/4x+1

Tom [10]

How I would do it is place a point at 1 then go up 1 over 4 because of your slope 1/4. Same as for going down except down 1 over 4. Hope this helped:)

5 0

3 years ago

What are the answers

dlinn [17]

Answer:

See below

Step-by-step explanation:

The ratio of the secants is the same when set up as full length to external length.

Formula

MN/LN = QN/PN

Givens

LN = 22 + 14 = 36

MN = 14

PN = 32

QN = x

Solution

14/36 = x / (32) Multiply both sides by 32

14*32 / 36 = x Combine 14 and 32

448/36 = x Divide by 36 and switch

x = 12.4

Answers

PN (External) = 13 is the closest answer

Length LN = 36

6 0

3 years ago

Help evaluating the indefinite integral

Dafna11 [192]

Answer:

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$

Derivative Property [Addition/Subtraction]:
$\displaystyle (u + v)' = u' + v'$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
$\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]:
$\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution/u-solve.

Set u:
$\displaystyle u = 4 - x^2$
[u] Differentiate [Derivative Rules and Properties]:
$\displaystyle du = -2x \ dx$
[du] Rewrite [U-Solve]:
$\displaystyle dx = \frac{-1}{2x} \ du$

Step 3: Integrate Pt. 2

[Integral] Apply U-Solve:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du$
[Integrand] Simplify:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du$
[Integral] Apply Integration Rule [Reverse Power Rule]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C$
[u] Back-substitute:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

∴ we have used u-solve (u-substitution) to find the indefinite integral.

---

Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0

2 years ago