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3 years ago

The zeroes of the function are . of the zeroes have a multiplicity of 2.

Mathematics

1 answer:

NISA [10]3 years ago

7 0

Answer:

The three roots have a multiplicity of 2

Step-by-step explanation:

The zeros of the function refers to those points on the x-axis on which the curve passes through

These are the points -2,0 and 4

Now we want to determine which of these points has a multiplicity of 2?

The correct answer is that all have a multiplicity of 2 since 2 can be factored out

2(-1) , 2(0) and 2(2)

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3m-2-5n+p terms and coefficients

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Answer: Answers are in the steps.

Step-by-step explanation:

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2 years ago

If -1 < x < 0 which of the following has the smallest value?

Katyanochek1 [597]

Answer: (B) x^3

Explanation:

If you compare the graphs of

y = x^2
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all on the interval -1 < x < 0, you'll find that y = x^3 is the smallest when x = -1

Squaring a negative number leads to a positive result, and similarly that happens with x^4 as well. This is because x^4 = (x^2)^2.

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2 years ago

Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position

Alenkinab [10]

Answer:

$\cos \theta=-\dfrac{8}{17}$

Step-by-step explanation:

Coordinates of Point b $=(-8,15)$

b lies on the circle whose equation is $x^2+y^2=289$

$x^2+y^2=17^2$

Comparing with the general form a circle with center at the origin: $x^2+y^2=r^2$

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

$\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}$

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