Adding all vakus in data set and divide by the number of values in the data set
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The probability of the television passing the test is p = 0.95
The sample size is n = 10
Generally the comprehensive testing process for all essential functions follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the probability that at least 9 pass the test is mathematically represented as
=> ![P(X \le 9) = [^{10}C_9 * (0.95)^9 * (1- 0.95)^{10-9}]+ [^{10}C_{10} * {0.95}^{10} * (1- 0.95)^{10-10}]](https://tex.z-dn.net/?f=P%28X%20%5Cle%209%29%20%3D%20%5B%5E%7B10%7DC_9%20%2A%20%20%280.95%29%5E9%20%2A%20%20%281-%200.95%29%5E%7B10-9%7D%5D%2B%20%5B%5E%7B10%7DC_%7B10%7D%20%2A%20%20%7B0.95%7D%5E%7B10%7D%20%2A%20%20%281-%200.95%29%5E%7B10-10%7D%5D)
=> ![P(X \le 9) = [10 * 0.6302 * 0.05 ]+ [1 *0.5987 * 1 ]](https://tex.z-dn.net/?f=P%28X%20%5Cle%209%29%20%3D%20%5B10%20%2A%20%200.6302%20%20%2A%200.05%20%5D%2B%20%5B1%20%2A0.5987%20%2A%201%20%5D%20)
=>
Answer:
Associative property - addition
Step-by-step explanation:
When three or more numbers are added, the sum is the same regardless of the way in which the numbers are grouped.
(6+2) + 5 = 6 + (2+5)
8 + 5 = 6 + 7
13 = 13
Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?
Answer:
the number is added to twice number is 99
