Answer:

Step-by-step explanation:
Given equation of ellipsoids,

The vector normal to the given equation of ellipsoid will be given by





Hence, the unit normal vector can be given by,



Hence, the unit vector normal to each point of the given ellipsoid surface is

Let's call the width of our rectangle
and the length
. We can say
, since the length is equal to 4 cm greater than the width.
Also remember that the perimeter of a rectangle is the sum of two times the width and two times the length, or
. To solve this problem, we can substitute in the information we know, as shown below:




Now, we can substitute in the width we found into the formula for length, which is
:


The width of our rectangle is
cm and the length of our rectangle is 
12x + 145 = 1345
12x = 1200
x = 100
answer: <span> She should save $100 each week so she can buy the laptop </span><span> for $1,345</span>
Answer:
46
Step-by-step explanation:
89
If this is for real, the answer is 163,840 horses on the farm, because 4^2 is 16, and 16^3 is 4,096, and 4,096 times 40 is 163,840.