Answer:

Step-by-step explanation:
Eliminating a negative and changing our operation

Rewriting our equation with parts separated

Solving the whole number parts

Solving the fraction parts
![-\frac{5}{6} +\frac{1}{4} =[?]](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D%20%2B%5Cfrac%7B1%7D%7B4%7D%20%3D%5B%3F%5D)
Find the LCD of 5/6 and 1/4 and rewrite to solve with the equivalent fractions.
LCD = 12

Combining the whole and fraction parts

[RevyBreeze]
So you want to solve for x?
It would be nice if this would easily factor:
(-4x + 5)(2x +1) = 0 This will not work!
So you need to use the quadratic formula:
a = -8, b = 4, c = 5

x = (-4 +/-

)/2(-8)
= (-4 +/-

)/-16
= (-4 +

)/-16
= 1/4 -

/4
If 1/3 = 12, then multiply 12 by 3 to get the number, which is 36
then split 36 in half, and you get 18.
hope this helps!
Answer:
C
Step-by-step explanation:
Using the coefficients of each term and evaluating for h = - 4
- 4 | 1 - 7 - 7 20
↓ - 4 44 - 148
---------------------------
1 - 11 37 - 128 ← remainder
Quotient = x² - 11x + 37 , R - 128
<em>Greetings from Brasil... </em>
A 1st degree function can be written in two ways:
F(X) = AX + B
or
Y = AX + B
note that F(X) = Y
So, looking at the alternatives in the question, only Y = 7X/3 - 8 is equivalent to Y = AX + B, where:
A = 7/3
B = - 8
then
<em>a function of the 1st degree</em>
answer:
<h2>Y = (7/3)X - 8</h2>