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elixir [45]
3 years ago
15

"if you add text, delete text, or modify text on a page, word recalculates the location of automatic page breaks and adjusts the

m accordingly."
a. True
b. False
Computers and Technology
2 answers:
Flura [38]3 years ago
8 0

Answer:

The answer to this question is option (a).

Explanation:

In the computer, all the data will store in a file that can be text file, image file, etc. All the file store data into (binary language that is (0,1)). In Microsoft Word or any other word software, we add, delete or modify any text that stores in file.  The software adjusts text location, memory, and breaks the pages automatically.

 So the correct answer to this question is option (a).  

Ann [662]3 years ago
4 0

Answer:

The given statement is true.

Explanation:

Whenever we add, delete or modify the contents in the word document, it automatically calculates the number of words. It adjusts the page breaks according to the number of encounter that we provide apart from modifying or adding the words and the number of backspaces that we enter after adding or while adding the contents.

The page break usually happens when a particular character encounters the “end of the page” and the whole word will be transferred to the next page. But still this “depends on the type of alignment”.

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What is the output of this code? import java.util.HashSet; class A { public static void main(String[ ] args) { HashSet set = new
kompoz [17]

Answer:

The code will give an error that is "At least one public class is required in main file".

Explanation:

In the given code if we do not use the public access modifier to the class. It will give an error so, the correct code to this question as follows:

Program:

import java.util.HashSet; //import package

public class A  //define class as public.

{

   public static void main(String[ ] args) //define main method.

   {

       HashSet set = new HashSet(); //creating hashset object.

       set.add("A"); //add alphabet in hashset

       set.add("B"); //add alphabet in hashset

       set.add("C"); //add alphabet in hashset

       System.out.print("Size of HashSet is :"set.size()); //print the size of hashset.

   }

}

Output:

Size of HashSet is : 3

Explanation of the program:  

  • In the above program, we define a public class that is "A" and inside the class, we define the main method.  
  • Inside the main method, we create a HashSet class object that is "set".  
  • To add elements in HashSet we use add() function that adds elements and in the last, we use the size() function that prints the size HashSet.
5 0
3 years ago
A direct-mapped cache holds 64KB of useful data (not including tag or control bits). Assuming that the block size is 32-byte and
Cerrena [4.2K]

Answer:

A) Number of bits for byte = 6 bits

B) number of bits for index = 17 bits

C) number of bits for tag = 15 bits

Explanation:

Given data :

cache size = 64 kB

block size = 32 -byte

block address = 32 -bit

number of blocks in cache memory  

cache size / block size = 64 kb / 32 b = 2^11 hence the number of blocks in cache memory = 11 bits = block offset

A) Number of bits for byte

log _{2} (6)^2 = 6  bits

B) number of bits for index

block offset + byte number

= 11 + 6 = 17 bits

c ) number of bits for tag

= 32 - number of bits for index

= 32 - 17 = 15 bits

5 0
3 years ago
Write a program that accepts 5 number and arrange them in ascending order​
Schach [20]
5
5 does this help?
5
5
5
7 0
3 years ago
in the world of computing accessibilty most often refers to: a how quickly software opens , b password protection, c assistance
Wittaler [7]
C. assistance for the disabled
8 0
3 years ago
"Hubs:
Butoxors [25]

Answer:

Hubs incorporate amplifiers and repeaters.

Explanation:

Hub is an outdated way of connecting ethernet devices, they incorporate amplifiers and repeaters, they do not allow simultaneous communication among connected devices.

The latest technology in connecting ethernet devices are with the use of switch.

7 0
3 years ago
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