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castortr0y [4]
3 years ago
15

hello my friend is doing a give away at 100 followers would you follow him for a chance to win 2000 vbucks his name is ZoVa_Velo

city on twitch
Computers and Technology
2 answers:
ratelena [41]3 years ago
8 0

Answer:

Awesome! Will do.

Mama L [17]3 years ago
7 0

Answer:

THIS IS A SCAM. JUST WARNING YA.

Explanation:

You might be interested in
What best describes "broadband access"?
Andre45 [30]

Answer:

The Correct option is : d. BROADBAND ACCESS enable users to connect to a high speed networks

Explanation:

As the names implies BROADBAND ACCESS can be defined as a technology that enables users to have the access to fast and high speed internet connection when browsing, streaming or downloading reason been that BROADBAND ACCESS is more faster and quicker which inturn enables the user to do a lot more on the internet which is why BROADBAND ACCESS is often refer or known as a high and fast speed Internet access connection.

5 0
3 years ago
8.11 LAB: Count characters - functions Write a program whose input is a character and a string, and whose output indicates the n
Shkiper50 [21]

Answer:

#include<iostream>

using namespace std;

int CountCharacters(char userChar, const string inputstr){

   int k = 0;

   int iter = 0;

   for (iter = 0; iter < inputstr.size(); iter++){

       if (inputstr[iter] ==  userChar){

           ++k;        }}

   return k;}

int main(){

   string str;

   char userChar[1];

   cout<<"Char: ";    cin>>userChar;

   cin.ignore();

   cout<<"String: ";   getline(cin, str);

   cout<<CountCharacters(userChar[0],str);

   return 0;}

Explanation:

Written in C++:

The function is defined here:

int CountCharacters(char userChar, const string inputstr){

This initializes a count variable k to 0

   int k = 0;

This initializes an iterating variable iter to 0

   int iter = 0;

This iterates through the characters of the string being passed to the function

   for (iter = 0; iter < inputstr.size(); iter++){

This checks for matching characters

       if (inputstr[iter] ==  userChar){

If found,  k is incremented by 1

           ++k;        }}

This returns the total count

   return k;}

The main begins here

int main(){

This declares a string variable

   string str;

This declares a character variable

   char userChar[1];

This gets input for the character variable

   cout<<"Char: ";    cin>>userChar;

This lets the user get another input

   cin.ignore();

This gets input for the string variable

   cout<<"String: ";   getline(cin, str);

This calls the function and return the count of character in the string

   cout<<CountCharacters(userChar[0],str);

6 0
3 years ago
Given the code that reads a list of integers, complete the number_guess() function, which should choose a random number between
Cerrena [4.2K]

Answer:

see explaination

Explanation:

import random

def number_guess(num):

n = random.randint(1, 100)

if num < n:

print(num, "is too low. Random number was " + str(n) + ".")

elif num > n:

print(num, "is too high. Random number was " + str(n) + ".")

else:

print(num, "is correct!")

if __name__ == '__main__':

# Use the seed 900 to get the same pseudo random numbers every time

random.seed(900)

# Convert the string tokens into integers

user_input = input()

tokens = user_input.split()

for token in tokens:

num = int(token)

number_guess(num)

5 0
3 years ago
To navigate through your presentation slides, which key on your keyboard can you use?<br> Dankonace
jekas [21]

Answer:

You use your arrow keys

Explanation:

4 0
3 years ago
A = [2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 33 34 35 36 37 38 39 40]
vova2212 [387]

Answer:

C = a./b

Explanation:

In MATLAB, the following command:

C = A./B

Performs the element by elemet division of A and B. This comand is called Right-array division.

So, in your case, we could divide A by B element by element, only using fully-vectorised code (ie. no loops), with the following code:

a = [2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 33 34 35 36 37 38 39 40];b = [1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 43 45 47 49 50 54 59 60];C = a./b;

C would be the element by element division of A and B, with no loops.

5 0
3 years ago
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