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iris [78.8K]
3 years ago
8

Safia opens a new savings account with a 2.25% simple interest rate. She deposits $3,500 and earned $3,696.88 total (with intere

st) by the time she checks the account again. How long was the money left untouched in the savings account?
Mathematics
1 answer:
Art [367]3 years ago
8 0

Answer:

The money was left untouched for 2 years and 6 months or just 2.5 years

Step-by-step explanation:

In this question, we are asked to calculate the time taken for an amount deposited to earn a certain amount of interest.

Mathematically, simple interest can be calculated using the formula;

I = PRT/100

where I is the interest accrued which is 3696.88 - 3,500 = 196.88

P is the principal which is the amount deposited = 3,500 according to the question

R is the rate which is 2.25% according to the question

T is the time which we are to find

we can rearrange the formula making T the subject and we obtain the following;

T = 100I/PR

substituting the values listed above we have;

T = (100 * 196.88)/(3500 * 2.25)

T = 19688/7875

T = 2.5 years or 2 years 6 months

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What does h(40) = 1700 mean in terms of the problem?
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Answer questions 13. And 14. Please! Show minimal work...
ale4655 [162]

13. The equation of the given function is y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

14. The equation of the cotangent function is y=cot[2(t-\frac{1}{3})]+2

Step-by-step explanation:

Let us revise the transformation of the trigonometric function:

y = a f[b(x + c)] + d, where

  • Amplitude is a
  • f represents the trigonometry function
  • Period is 2π/b
  • Phase shift is c (positive is to the left)
  • Vertical shift is d

13.

∵ y = a sin( \frac{2\pi t}{T} ), where a is the amplitude

   and T is the wave in seconds

∵ The amplitude is 4

∴ a = 4

∵ The period is 4π

∴ T = 4π

From the rules above

∵ The period is 2π/b

∴ T = \frac{2\pi }{B}

∴ 4π = \frac{2\pi }{b}

- By using cross multiplication

∴ 4π(b) = 2π

- Divide both sides by 4π

∴ b = \frac{1}{2}

∵ The phase shift is -\frac{4}{3}\pi

∵ c is the phase shift

∴ c = -\frac{4}{3}\pi

∵ The vertical shift is -2

∵ d is the vertical shift

∴ d = -2

Now substitutes the values of a, b, c and d in the form of the equation below

∵ y = a sin[b(t + c)] + d

∴ y=4sin[\frac{1}{2}(t-\frac{4}{3})]-2

You can write it as y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

The equation of the given function is y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

14.

y = cot[b(t + c)] + d

∵ The period = π

∵ The period is 2π/b

- Equate π by 2π/b to find b

∴ π = \frac{2\pi }{b}

- By using cross multiplication

∴ π(b) = 2π

- Divide both sides by π

∴ b = 2

∵ The phase shift is -\frac{1}{3}\pi

∵ c is the phase shift

∴ c = -\frac{1}{3}\pi

∵ The vertical shift is 2

∵ d is the vertical shift

∴ d = 2

Now substitutes the values of b, c and d in the form of the equation below

∵ y = cot[b(t + c)] + d

∴ y=cot[2(t-\frac{1}{3})]+2

The equation of the cotangent function is y=cot[2(t-\frac{1}{3})]+2

Learn more:

You can learn more about trigonometry function in brainly.com/question/3568205

#LearnwithBrainly

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