Two cards are chosen at random without replacement from a pack of 52 playing cards if the first card chosen is an Ace what is th e probability the second card chosen is also an ace
2 answers:
So originally you have 52 cards which means that no matter what card you want it'll be a 1/52 chance pulling that exact card. You pull an Ace which gives you 51 cards left, and a 1/51 chance of pulling the card you want. You want another Ace, and since it's a full deck of cards means that there should be 3 Aces left in the deck. Probability of pulling another Ace is 3/51. Hope this Helps.
Since we removed one ace out of 52 cards now remains 51 cards and 3 aces. The answer is 3/51
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Answer:
x(x-5) = 14
x^2-5x-14 = 0
x^2 -7x+2x-14=0
x(x-7)+2(x-7)=0
(x+2)(x-7)=0
x = -2, 7
Hope this helps!
All of them are true.
Refer to calculation for understanding.
Mean is 750 and mode is 850
Answer:
15 days
Step-by-step explanation:
You'd divide 40 by 2 2/3, getting you 15.Therefore there will be enough food for the dog to eat for 15 days.