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Gennadij [26K]
3 years ago
7

Two cards are chosen at random without replacement from a pack of 52 playing cards if the first card chosen is an Ace what is th

e probability the second card chosen is also an ace
Mathematics
2 answers:
jonny [76]3 years ago
7 0
So originally you have 52 cards which means that no matter what card you want it'll be a 1/52 chance pulling that exact card.

You pull an Ace which gives you 51 cards left, and a 1/51 chance of pulling the card you want.

You want another Ace, and since it's a full deck of cards means that there should be 3 Aces left in the deck.

Probability of pulling another Ace is 3/51. Hope this Helps.
Amiraneli [1.4K]3 years ago
5 0
Since we removed one ace out of 52 cards now remains 51 cards and 3 aces.
The answer is 3/51
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Using vector concepts, it is found that:

The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.

<h3>How can a vector be represented in component notation?</h3>

Given a magnitude M and angle \theta, then a vector V can be represented as follows in component notation:

V = (M\cos{\theta}, M\sin{\theta})

In this problem, the magnitude and the angle are given, respectively, by:

M = 12, \theta = 143^\circ

Hence:

V = [12cos(143º), 12sin(143º)] = (-9.58, 7,22).

Which means a displacement of 9.58 miles to the west(negative x = west) and 7.22 miles to the north(positive y = north).

The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.

More can be learned about vectors at brainly.com/question/24606590

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Brrunno [24]

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