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Gennadij [26K]
3 years ago
7

Two cards are chosen at random without replacement from a pack of 52 playing cards if the first card chosen is an Ace what is th

e probability the second card chosen is also an ace
Mathematics
2 answers:
jonny [76]3 years ago
7 0
So originally you have 52 cards which means that no matter what card you want it'll be a 1/52 chance pulling that exact card.

You pull an Ace which gives you 51 cards left, and a 1/51 chance of pulling the card you want.

You want another Ace, and since it's a full deck of cards means that there should be 3 Aces left in the deck.

Probability of pulling another Ace is 3/51. Hope this Helps.
Amiraneli [1.4K]3 years ago
5 0
Since we removed one ace out of 52 cards now remains 51 cards and 3 aces.
The answer is 3/51
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(- 4, - 10 )

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the table shows the cost of the daycare for Lucy's dog this week her dog went 3 full days of day care and 2 half days of day car
drek231 [11]

An expression for the total cost of the daycare for Lucy's dog this week is T = 3F + 2H and the total cost is equal to $114.

<h3>How to write an expression for the total cost?</h3>

In this exercise, you're required to write an expression for the total cost of the daycare for Lucy's dog this week. Thus, we would assign a variable to the cost for full-day and half-day day care as follows:

  • Let the cost for full-day be F.
  • Let the cost for half-day be H.
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Thus, the total cost of the daycare is given by:

T = 3F + 2H

Evaluating the expression, we have:

T = 3(28) + 2(15)

T = 84 + 30

T = $114.

Read more on expressions here: brainly.com/question/12189823

#SPJ1

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2 years ago
Identify the number types that describe a bar over 7
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Answer:Type of Number Example

Prime Number P=2,3,5,7,11,13,17,…

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Whole Numbers W=0,1,2,3,4,…

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Step-by-step explanation:

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2 years ago
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