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fomenos
3 years ago
9

The interior ages of a triangle have measure

Mathematics
2 answers:
Solnce55 [7]3 years ago
8 0
Answer:
100 degrees just think about how all the angles in a triangle add up to 180 degrees
Nina [5.8K]3 years ago
3 0

Answer:

See below in bold.

Step-by-step explanation:

1. The 3 angles in a triangle add up to 180 degrees.

So x = 180 - (55 + 25)

= 180 - 80

= 100 degrees.

2.  The 4 angles in a quadrilateral add up to 360 degrees,, so

3x + 127 + 54 + 119 = 360

3x + 300 = 360

3x = 360 - 300

3x = 60

x = 20 degrees.

3. Exterior angle

= 94 + 42

= 136 degrees.

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Find the values of x and y for the isosceles trapezoid
butalik [34]
<h3>Answer:</h3>
  • x = 15
  • y = 3
<h3>Step-by-step explanation:</h3>

If the trapezoid is isosceles, angles A and C are supplementary, so ...

... (4x+4) +(7x+11) = 180

... 11x +15 = 180 . . . . . . collect terms

... 11x = 165 . . . . . . . . . subtract 15

... x = 15 . . . . . . . . . . . . divide by the coefficient of x

And angles C and E are congruent.

... 4·15 +4 = 21y +1

... 63 = 21y . . . . . subtract 1

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4 0
3 years ago
Help me please !!!!!!!!
777dan777 [17]

y=5/3x

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If you were to do y=x+5/3 it would make a horizontal shift to the left 5/3

So the unit your on is mostly about knowing the number located in the function that will make the graph shift different ways

8 0
3 years ago
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faltersainse [42]
= -4-(-1)
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7 0
3 years ago
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Montano1993 [528]
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3 years ago
A low P-Value in ANOVA table mean that the population mean of each treatment effects are different. the population mean of at le
Verizon [17]

Answer:

The population mean of at least one treatment effect are different.

Step-by-step explanation:

An analysis of variance (ANOVA) is conducted in order to determine if there are significant differences between the values of the population mean with respect to the response variable for the domains that under the effects of different treatments. A low p-value leads to reject the null hypothesis of the following hypothesis system:

H_0: \mu_1=\mu_2=...=\mu_k\\\\\\H_a: \mu_i \neq\mu_j, for $ for some i, j between 1 and k.$

Rejecting H0 means that this hypothesis is false and, in turn, allows us to conclude that the population mean of one of the domains is different from the others.

4 0
4 years ago
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