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3 years ago

Prime factorization of 55

Mathematics

2 answers:

zheka24 [161]3 years ago

8 0

Answer:

5 × 11

Step-by-step explanation:

Scilla [17]3 years ago

8 0

Answer: 5x11

Explanation: because the prime factorization of a number means the prime numbers that can multiply together to get another number. Ex. 2 and 3 are prime numbers, and 2x3=6, so the prime factorization of 6 is 2x3.

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What is 17- 6 11/12.

Naddika [18.5K]

Answer:

10 1/12

Step-by-step explanation:

17-6 is 11

11-11/12=

10 1/12

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4 years ago

For Thanksgiving, a family of 9 is trying to share 4 store-bought pies fairly. If each pie is pre-cut into 8 slices, and everyon

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3 years ago

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

4 years ago

A square ceiling has a diagonal of 24 ft. Shelton wants to put molding around the perimeter of the ceiling.

Alina [70]

Square has all perimeter lines identical. to find the length of a side you can use a^2 = b^2 + c^2
24^2 = 576

as b and c are equal you can just divide 576 by 2 to get 288.
square root of 288 = 16.97 feet

6 0

3 years ago

Read 2 more answers

Thank u for all the amazing answers everyone :)

Dennis_Churaev [7]

I'm sorry if I wasn't there to help but thank the others, and thank you :)

5 0

3 years ago

Read 2 more answers