<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
Complete question :
Wang Yong owes the bank $8500. To repay the debt, he paid a fixed amount back to the bank each month. After 12 months, his remaining debt was $6460. How much did Wang Yong pay each month?
Answer:
$170
Step-by-step explanation:
Given that:
Amount owed = $8500
Fixed amount replayed per month :
Amount left after 12 months = $6460
Amount paid per month :
Total amount paid over 12 months :
$(8500 - 6460) = $2040
Amount paid per month :
$2040 / 12
= $170
Im not sure if you wrote this wrong because (x+y)2 does equal x2+y2. An example would be if x equals 3 and y equals 4 (3+4)2=(3)2+(4)2 (7)2=6+8 14=14.
Answer:
The Answer is B
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here diameter = 12, thus radius = 12 ÷ 2 = 6 and (h, k) = (2.5, - 3.5), thus
(x - 2.5)² + (y - (- 3.5))² = 6², that is
(x - 2.5)² + (y + 3.5)² = 36 ← equation of circle
Answer:
what do you mean by graph
Step-by-step explanation: